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Anarel [89]
3 years ago
5

There are some red and blue balls in a bag of 21 balls and the probability of picking 2 red balls out in a row is 1/14 how many

red balls are there?
Mathematics
2 answers:
Over [174]3 years ago
8 0

Answer:

6 red balls

Step-by-step explanation:

The probability in the first pick

6/21

The probability in the second pick (without replacement)

5/20

the requested probability

(6/21)(5/20) = 30/420

simplification

30/420 = 3/42 = 1/14

Hope this helps

VMariaS [17]3 years ago
5 0

Answer:

6 red balls.

Step-by-step explanation:

If there are x red balls then

probability of 2 red balls

= x/21 * (x - 1)/20 = 1/14

x^2 - x / 420 = 1/14

x^2 - x = 30

x^2 - x - 30 = 0

(x - 6)(x + 5) = 0

x = 6.

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The difference is 7x^{2}  + 1x-7.

Step-by-step explanation:

Step 1:

The polynomial -5x^{2}+3x+8 is subtracted from the polynomial 2x^{2} + 4x +1.

If we write this as an equation, we get

(2x^{2} + 4x +1) -(-5x^{2}+3x+8).

To subtract the polynomials, we group up the terms based on their variables.

In this subtraction, there are two variables i.e. x^{2} and x and there is one constant term.

Step 2:

The subtraction of the x^{2} variables; 2x^{2}  -(-5x^{2} )  = 2x^{2} +5x^{2} = 7x^{2}.

The subtraction of the x variables; 4x - (3x) = 1x.

The subtraction of the constants; 1-(8) = -7.

So (2x^{2} + 4x +1) -(-5x^{2}+3x+8) = 7x^{2}  + 1x-7.

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