All categories

3 years ago

Pls help i neeed to get my grade up badly

Mathematics

1 answer:

amm18123 years ago

5 0

Step-by-step explanation:

12 - 1/2r = ( 13 - 3/2r ) - ( 1 - r )

r - 13/6 = ( 7r - 3/2 ) - ( 2/3 + 6r )

13r + 20 = ( 6r + 7 ) + ( 13 + 7r )

-12 + r = ( -8 - r ) + ( 2r - 4 )

You might be interested in

Pls help with iready question

iragen [17]

If the "some number" is represented by m, then "some number cubed" is m^3. The product of that and 2 is 2m^3. Eight more than that product is
.. 8 +2m^3 . . . . . . . . upper-left selection

6 0

4 years ago

Read 2 more answers

Which statement is NOT true?

elena-s [515]

If x ^ 2 = 100, then x = 10.

For this case what you should know is the correct clearance of the following equation:
$x ^ 2 = 100
$
We then have two possible solutions:
$x=+/- \sqrt{100}$
Rewriting we have:
$x=+/-10$
Therefore, the solutions are:
$x1=10

x2=-10$
Answer:
A statement that is NOT true is:
If x^2 = 100, then x = 10.

3 0

3 years ago

In scientific notation, 330 is written: 3.3 x (10^2) 33 x (10^2) 3.3 x (10^3) 3.3 x (10^4)

Rom4ik [11]

In scientific notation, it would be:

A)3.3*10^2

4 0

3 years ago

Read 2 more answers

Let g(x, y) = cos(x + 5y). (a) Evaluate g(10, −2). g(10, −2) = (b) Find the domain of g. −1 ≤ x ≤ 1, − 1 5 ≤ y ≤ 1 5 −5 ≤ x ≤ 5,

RoseWind [281]

Answer:

since $Cos(z)$ is a function defined for all $z\in \mathbb{R}$ , then there is not restriction for $x+5y$ , thus, the domain of $g(x,y)$ is $\mathbb{R}^2$ and in interval notation is $(-\infty,\infty)\times(-\infty,\infty)$

Since $Cos(x+5y)\in\mathbb{R}$ then the range of $g(x,y)$ is the interval [-1,1].

4 0

4 years ago

<img src="https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D%20n-%5Cfrac%7B1%7D%7B6%7D%20%3D-%5Cfrac%7B1%7D%7B3%7D%20%2B%5Cfrac%7B11

mel-nik [20]

Answer:

n = -2

Step-by-step explanation:

$\frac{-5}{6}n-\frac{1}{6}=\frac{-1}{3}+\frac{11}{6}\\\\\frac{-5}{6}n=\frac{-1}{3}+\frac{11}{6}+\frac{1}{6}\\\\\frac{-5}{6}n=\frac{(-1)*2}{3*2}+\frac{11}{6}+\frac{1}{6}\\\\\frac{-5}{6}n=\frac{-2}{6}+\frac{11}{6}+\frac{1}{6}\\\\\frac{-5}{6}n=\frac{-2+11+1}{6}\\\\\frac{-5}{6}n=\frac{10}{6}\\\\n=\frac{10}{6}*\frac{6}{-5}\\\\n= -2$

4 0

3 years ago