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Iteru [2.4K]
3 years ago
8

An integrated collection of information that is logically related and stored to minimize duplication and facilitate rapid retrie

val is called a ________. data dictionary database data definition dataset
Computers and Technology
1 answer:
ankoles [38]3 years ago
6 0

the answer is database. Hope this helps thank u

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In order to manage information for a company, your website would need a/an
Eva8 [605]
The answer is database.
3 0
3 years ago
What are the differences between message confidentiality and message integrity? Can you have confidentiality without integrity?
Artist 52 [7]

Answer:

message confidentiality

Two or more hosts communicate securely, typically using encryption. The communication cannot be monitored (sniffed) by non trusted hosts. The communication between trusted parties is confidential.

message integrity

The message transported has not been tampered with or altered. A message has integrity when the payload sent is the same as the payload received.

Sending a message confidentially does not guarantee data integrity. Even when two nodes have authenticated each other, the integrity of a message could be compromised during the transmission of a message.

Yes, you can have integrity of a message without confidentiality. One can take a hash or sum of the message on both sides to compare. Often we share downloadable files and provide data integrity using md5 hash sums.

Explanation:

3 0
3 years ago
Suppose you have a 12-hour clock on a very fancy chair (noon is 12 PM and midnight is 12 AM). Write a C++ program that reads in
agasfer [191]

Answer:

#include<iostream>

#include<cmath>

#include <ctime>

using namespace std;

int main()

{

       time_t t = time(NULL);

tm* timePtr = localtime(&t);

cout << "seconds= " << (timePtr->tm_sec) << endl;

cout << "minutes = " << (timePtr->tm_min) << endl;

cout << "hours = " << (timePtr->tm_hour) << endl;

cout << "day of month = " << (timePtr->tm_mday) << endl;

cout << "month of year = " << (timePtr->tm_mon)+1 << endl;

cout << "year = " << (timePtr->tm_year)+1900 << endl;

cout << "weekday = " << (timePtr->tm_wday )<< endl;

cout << "day of year = " << (timePtr->tm_yday )<< endl;

cout << "daylight savings = " <<(timePtr->tm_isdst )<< endl;

       cout << endl;

       cout << endl;

       cout << "Date     " <<(timePtr->tm_mday)<<"/"<< (timePtr->tm_mon)+1 <<"/"<< (timePtr->tm_year)+1900<< endl;

       cout << "Time     " << (timePtr->tm_hour)<<":"<< (timePtr->tm_min)<<":"<< (timePtr->tm_sec) << endl;  

   return 0;

}

Explanation:

4 0
3 years ago
How can migrating to an enterprise platform solution help a business improve employee productivity?
Lorico [155]

Answer:

By allowing all employees to access and share the same stored dats and by increasing the number of wmployees in business activities

Explanation:

#<em>carry on learning</em>

5 0
3 years ago
Let's write a simple markdown parser function that will take in a single line of markdown and be translated into the appropriate
Klio2033 [76]

Answer:

Here is the answer in Java with appropriate comments for understanding

Explanation:

import java.util.Scanner;

public class Hash {

public static void main(String[] args) {

System.out.print("Enter a string : ");

Scanner scanner = new Scanner(System. in);

String s = scanner. nextLine();   //read string

int k=s.lastIndexOf('#'),count=0;//find last occurence of # then take the next part

  String s2="",s3="";

  for(int i=0;i<s.length();i++)

  {

      if(s.charAt(i)=='#')

          count++;//count the occurence of # of level of heading h1,h2,h3,....

  }

  for(int j=k+1;j<s.length();j++)

  {

      s2+=s.charAt(j);//take the remainging string after #

  }

// System.out.println(k);

 

//System.out.println(count);

if(count<=6)//if it is valid heading

{

  s3="<h"+count+">"+s2+"</h"+count+">";

  System.out.println(s3);  

}

else

  System.out.println("Invalid header");

 

}

}

6 0
3 years ago
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