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nevsk [136]
2 years ago
11

2zx2y=18 where x=1,z=y

Mathematics
2 answers:
Bad White [126]2 years ago
5 0

\huge \bf༆ Answer ༄

Let's plug the given values and find value of y ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2zx2y = 18

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2 \times y \times 1 \times 2 \times y = 18

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:4 {y}^{2}  = 18

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:{y}^{2}  =  \dfrac{18}{4}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y {}^{2}  = 4.5

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y =  \sqrt{4.5}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y =  \sqrt{9 \times 0.5}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 3 \sqrt{ \frac{5}{10} }

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:3 \sqrt{ \frac{1}{2} }

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \dfrac{3}{ \sqrt{2} }

or, you can further simplify it to ;

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2.12 \:  \:  (upto \:  \: two \: decimals)

QveST [7]2 years ago
3 0
Plug in the values: 2(y)(1)2y=18
First multiply 1 with 2y = 2y(2y)=18
Second multiply 2y and 2y = 4y^2=18
Third divide both sides by 4 = 4y^2/4=18/4
—-> y^2=9/2
Fourth square root both sides = y= √ 9/2 (in square root)
If you need to simplify further you would get 3 √2/2
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