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nevsk [136]
2 years ago
11

2zx2y=18 where x=1,z=y

Mathematics
2 answers:
Bad White [126]2 years ago
5 0

\huge \bf༆ Answer ༄

Let's plug the given values and find value of y ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2zx2y = 18

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2 \times y \times 1 \times 2 \times y = 18

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:4 {y}^{2}  = 18

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:{y}^{2}  =  \dfrac{18}{4}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y {}^{2}  = 4.5

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y =  \sqrt{4.5}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y =  \sqrt{9 \times 0.5}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 3 \sqrt{ \frac{5}{10} }

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:3 \sqrt{ \frac{1}{2} }

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: \dfrac{3}{ \sqrt{2} }

or, you can further simplify it to ;

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2.12 \:  \:  (upto \:  \: two \: decimals)

QveST [7]2 years ago
3 0
Plug in the values: 2(y)(1)2y=18
First multiply 1 with 2y = 2y(2y)=18
Second multiply 2y and 2y = 4y^2=18
Third divide both sides by 4 = 4y^2/4=18/4
—-> y^2=9/2
Fourth square root both sides = y= √ 9/2 (in square root)
If you need to simplify further you would get 3 √2/2
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A recent Gallup poll found that 36% of U.S. teens aged from 13 to 17 years old have a computer with [(6)] Internet access in the
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Answer:

Step-by-step explanation:

a) The population parameter is the population proportion.

b) Confidence interval is written as

Sample proportion ± margin of error

Margin of error = z × √pq/n

Where

z represents the z score corresponding to the confidence level

p = sample proportion. It also means probability of success

q = probability of failure

q = 1 - p

p = x/n

Where

n represents the number of samples

x represents the number of success

From the information given,

n = 1028

p = 36/100 = 0.36

q = 1 - 0.36 = 0.64

To determine the z score, we subtract the confidence level from 100% to get α

α = 1 - 0.99 = 0.1

α/2 = 0.01/2 = 0.005

This is the area in each tail. Since we want the area in the middle, it becomes

1 - 0.05 = 0.995

The z score corresponding to the area on the z table is 2.58. Thus, confidence level of 99% is 2.58

Therefore, the 99% confidence interval is

0.36 ± 2.58 × √(0.36)(0.64)/1028

The lower limit of the confidence interval is

0.36 - 0.039 = 0.321

The upper limit of the confidence interval is

0.36 + 0.039 = 0.399

Therefore, with 99% confidence interval, the proportion of U.S. teens aged from 13 to 17 years old that have a computer with Internet access in their rooms is between 0.321 and 0.399

c) for a margin of error of 1%, that is 1/100 = 0.01, then

0.01 = 2.58 × √(0.36)(0.64)/n

0.01/2.58 = √0.2304/n

0.00387596899 = √0.2304/n

Square both sides

0.00001502314 = 0.2304/n

n = 0.2304/0.00001502314

n = 15336

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