3 years ago

PLZ HURRY Solve for g.g3 – 1 > 2

Mathematics

1 answer:

Phoenix [80]3 years ago

5 0

$g3 - 1 > 2$

$g3 - 1 + 1 > 2 + 1$

$g3 > 3$

$\frac{g3}{3} > \frac{3}{3}$

$g > 1$

If the 3 is an exponent, then the person above me is right.

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