We are given that
Shopkeeper has six coins
total number of coins =6
we know that
there are four types of coins
(1) cents
1 cent =1 cent
(2) nickels
1 nickel =5 cents
(3) dimes
1 dimes =10 cents
(4) quarters
1 quarter = 25 cents
so, we can use trial and error method
Since, nickels , dimes and quarter are multiple of 5
and there 38 cents
so, three coins must be cent
number of cent coins =3
so, the remaining cent = 38-3=35
so, possible coins can be 1 quarter and 2 nickels
1 quarter + 2 nickels =25+2(5)=35
so, coins were
Number of cents =3
Number of nickels =2
Number of dimes =0
Number of quarter =1..................Answer
Answer:
though this is difficult i know you would get it. Anyhow im real tired... will solve later... gl
Answer:
The roots can be seen from the graphs as - 4 and +4
The equation is :
x² - (sum of roots) + (product of roots)
Equation is x² -16
I hope you got it
Y=65
X=5
X=12
Y=?
65—->5
?——>12
Cross multiply
Y= (65x12) / 5
Y= 780 / 5
Y= 156
To check add the Y value in and remove an X value
65——> ?
156 ——> 12
Cross multiply
X= (12x65) / 156
X= 780 / 156
X= 5
You got the right answer. Hope this helped.
