1) Reduza os números abaixo a uma potência de base 2
2 answers:
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Answer:
The answer is D. 0.75
Step-by-step explanation:
Let call R the event that a person is rascal, RC a person is not rascal, TH a person use top hat and NTH a person don’t use top hat.
From the information on the question we have 4 options with their respective probability:
1. A person could be rascal and use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and use a top hat (0.9), then:
P(R y TH)=0.5*0.9=0.45
2. A person could be rascal and don’t use top Hat: this probability is calculate as the multiplication of the probability of be a rascal (0.5) and not use a top hat (0.9), then:
P(R y NTH)=0.5*0.1=0.05
3. A person could be not rascal and use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and use a top hat (0.3), then:
P(RC y TH)=0.5*0.3=0.15
4. A person could be not rascal and not use top Hat: this probability is calculate as the multiplication of the probability of not be a rascal (0.5) and not use a top hat (0.7), then:
P(RC y NTH)=0.5*0.7=0.35
Then the probability that a person is a rascal given that he is wearing a top hat could be written and calculate as:
For calculate P(TH) we need to sum all the option in which TH is involve so:
P(TH) = P(R y TH)+ P(RC y TH)
P(TH)=0.45+0.15=0.6
Replacing values on the first equation we get:
So, the probability that a person is a rascal given that he is wearing a top hat is 0.75
All the numbers in this range can be written as 
with 
and 
. Construct a table like so (see attached; apparently the environment for constructing tables isn't supported on this site...)
so that each entry in the table corresponds to the sum of the tens digit (row) and the ones digit (column). Now, you want to find the numbers whose digits add to perfect squares, which occurs when the sum of the digits is either of 1, 4, 9, or 16. You'll notice that this happens along some diagonals.
For each number that occupies an entire diagonal in the table, it's easy to see that that number
shows up times in the table, so there is one instance of 1, four of 4, and nine of 9. Meanwhile, 16 shows up only twice due to the constraints of the table.
So there are 16 instances of two digit numbers between 10 and 92 whose digits add to perfect squares.
so that each entry in the table corresponds to the sum of the tens digit (row) and the ones digit (column). Now, you want to find the numbers whose digits add to perfect squares, which occurs when the sum of the digits is either of 1, 4, 9, or 16. You'll notice that this happens along some diagonals.
For each number that occupies an entire diagonal in the table, it's easy to see that that number
So there are 16 instances of two digit numbers between 10 and 92 whose digits add to perfect squares.