This is fairly easy.
The second choice would be the option here because the greater numbers are always on the right while the lower numbers are on the left.
Hope this helps!
<h2>
Range of x </h2><h3>
and x>6</h3><h3>
Step-by-step explanation:</h3>
Given AB = 4x + 5, BC = 3x - 2 and AC 9x -5
The sum of the length of any two sides of a triangle is greater than the length of third side.
Case I
AB + BC > AC
⇔4x +5 +3x -2 > 9x -5
⇔7x + 3 >9x - 5
⇔ 7x -9x > -5 -3
⇔-2x > -8
⇔x <4
Case II
if AB+AC > BC
4x +5 +9x -5> 3x -2
⇔13x >3x -2
⇔ 13x -3x> -2
⇔10x > -2
⇔x >
Case III
AC+BC > AB
⇔9x - 5 +3x - 2 > 4x +5
⇔6x -7 > 4x +5
⇔6x -4x >5+7
⇔2x > 12
⇔x > 6
Let x be the distance from Syracuse where they pass. The first car travels a distance of x in time x/65 while the second car travels a distance 240-x in time (240-x)/55. They pass at the same time after leaving their starting points so x/65=(240-x)/55.
Cross-multiplying we get: 55x=65(240-x)=15600-65x, 120x=15600, x=15600/120=130 miles.
They pass 130 miles from Syracuse.
3:7 =
3/7
3/7 = x/35
7x = 105
x = 15
answer : clara borrowed 15 books