Check the problem again!Cosecant (csc) is the reciprocal of sine (sin) so they are always either both positive or both negative. Perhaps it should be sine < 0 and cosine > 0? In that case, sine is less than zero in quadrants 3 and 4, and cosine is greater than zero in quadrants 1 and 4, so this angle can only lie in quadrant 4. On the unit circle, remember that cosine is the x-coordinate of the terminal side of the angle and sine is the y-coordinate. Quadrant 1 is that where both sine and cosine are greater than zero. The rest of them are numbered consecutively going counter-clockwise; so quadrant 2 has cos < 0 and sin > 0, quadrant 3 has cos < 0 and sin < 0, and quadrant 4 has cos > 0 and sin < 0
Answer:
x = 35
Step-by-step explanation:
Let x be the one of the other angles
X is also the third angle since we know they are equal
The sum of the angles of a triangle is 180
110+x+x = 180
110 +2x= 180
2x = 180-110
2x= 70
Divide by 2
2x/2 = 70/2
x = 35
Step-by-step explanation:
They both have the same gradient of 1. (Their slope is 1)
Answer:
Step-by-step explanation:
If you mean slope.. the equation to set up is y=mx+b. Using this, and finding out the answer m=2.
Hope this helped!
