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Sedbober [7]
2 years ago
11

What is the smallest number that is a multiple of both 4 and 6

Mathematics
2 answers:
lana66690 [7]2 years ago
5 0

Answer:

2

Step-by-step explanation:

4 2x2 is 4

2x3 is 6

sorry for the long type it says 20 character above

Finger [1]2 years ago
4 0
The smallest multiple of the numbers would be 2
You might be interested in
5x4 - 7x3 + x + 2 <br> terms
Tomtit [17]

Answer:

It is already the farthest that can be

Step-by-step explanation:

5x4 - 7x3 + x + 2

5x^2 - 7x^2 + 1x + 2

7 0
3 years ago
What is product of x/3 and 6/x when x=0 ? <br>A.2 <br>B.18 <br>C.2/x^2<br> D.18/x^2
Ahat [919]

Answer:

A) But if anyone thinks this they should go back to preschool

Step-by-step explanation:

On any other value of x you would take the numerators and denominators and multiply them across:

\frac{x}{3}*\frac{6}{x}=\frac{x*6}{x*3}=\frac{6}{3} =2

But, this literally does not make since considering the fact that you cannot divide any value by zero. Try it, it won't work. If we plug these into a trusty dusty calculator, we get this:

\frac{0}{3}=0\\\\\frac{6}{0}=DOMAINERROR

0*DOMAINERROR= You can't do it.

There are other reasons why you can't divide by zero, I would suggest looking them up on YT and learning about them.

I would answer A, but the person who wrote this question just wasn't focusing when they wrote the question.

4 0
3 years ago
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by
11111nata11111 [884]

Answer:

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is 8.217 cubic inches.

Step-by-step explanation:

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the open rectangular box ?

Solution :

Let the height be 'x'.

The length of the box is '11-2x'.

The breadth of the box is '7-2x'.

The volume of the box is V=l\times b\times h

V=(11-2x)\times (7-2x)\times x

V=4x^3-36x^2+77x

Derivate w.r.t x,

V'(x)=4(3x^2)-2(36x)+77

V'(x)=12x^2-72x+77

The critical point when V'(x)=0

12x^2-72x+77=0

Solve by quadratic formula,

x=\frac{18+\sqrt{93}}{6},\frac{18-\sqrt{93}}{6}

x=4.607,1.392

Derivate again w.r.t x,

V''(x)=24x-72

Now, V''(4.607)=24(4.607)-72=38.568>0 (+ve)

V''(1.392)=24(1.392)-72=-38.592 (-ve)

So, there is maximum at x=1.392.

The length of the box is l=11-2x

l=11-2(1.392)=8.216

The breadth of the box is b=7-2x

b=7-2(1.392)=4.216

The height of the box is h=1.392.

The dimension of the open rectangular box is 8.216\times 4.216\times 1.392.

The volume of the box is V=l\times b\times h

V=8.216\times 4.216\times 1.392

V=48.217\ in.^3

The volume of the box is 8.217 cubic inches.

5 0
3 years ago
What expression is equivalent to the square root of -80
Ganezh [65]

Answer:

Step-by-step explanation:

√-80

7 0
3 years ago
Read 2 more answers
HELP MEEE PLEASE ILL MARK BRIANLIST!!!!
Aleksandr-060686 [28]
The points in order from top to bottom are :

F
E
C
H
I
5 0
3 years ago
Read 2 more answers
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