Answer:
The first 5 terms are;
-2, 2, 13,38 and 91
Step-by-step explanation:
Here, we want to write the first 5 terms of the sequence.
We already have the first term as 1
Now, we need the 2nd term
Putting two in place of n, we have ;
2f(1) + 3n
= 2(-2) + 3(2) = -4 + 6 = 2
For the 3rd term, put 3 in place of n
2f(2) + 3(3)
sine f(2) = 2, we have
2(2) + 9 = 4+ 9 = 13
For the fourth term, put 4 in place of n, we have
2f(3) + 3(4)
since f(3) = 13
we have; 2(13) + 12 = 26 + 12 = 38
For the 5th term, put 5 in place of n, we have
2f(4) + 3(5)
since f(4) = 38, we have
2(38) + 15 = 76 + 15 = 91
8x3.5= ? That’s gonna be your answer.
Answer:
Step-by-step explanation:
x-intercepts are SOLUTIONS to a quadratic whereas when you put those solutions into factor form (in a set of parenthesis), you have the FACTORS of the quadratic. They are the same thing generally, they are just written in different forms. For example, if a solution to a quadratic is x = 3, it has been understood that x = 3 when y = 0. Therefore, if x - 3 = y and y = 0, then x - 3 = 0. Solving that for x, you get x = 3. That factor of x = 3 is (x - 3).
Following that logic, for a:
If the x intercepts are x = 0 and x = 3, it is understood that x + 0 = 0 so x = 0 and the factor is (x + 0) (it could also be x - 0 since adding 0 is the same as subtracting 0); if x = 3 it is understood that x - 3 = 0 and the factor is (x - 3).
For b:
If the x-intercepts are x = -1 and x = 1, then originally the factors were (x + 1) and (x - 1). Again, set each of those equal to 0 and solve for x (THE X-INTERCEPT EXISTS WHERE Y = 0!)
For c:
If the x-intercepts are x = -5 and x = 10, then originally the factors were (x + 5) and (x - 10).
For d:
If the x-intercept is a fraction, do the same thing:
x = 1/2 so
x - 1/2 = 0 Now multiply both the x and the 1/2 by a 2 to get the factor (2x - 1) and the other factor from x = 4 is (x - 4)
36x - 20 = 160
+ 20 + 20
36x = 180
—— ——
36 36
ANSWER: x = 5
Answer:
2,065.00
Step-by-step explanation:
