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PtichkaEL [24]
2 years ago
7

Find the missing number.

Mathematics
2 answers:
navik [9.2K]2 years ago
7 0

Answer:

25% - from 180 degrees

Step-by-step explanation:

Galina-37 [17]2 years ago
4 0
25% - from 180 degrees
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If a planet takes longer to travel around the sun, than earth, what has changed?
Crazy boy [7]

Answer:

the years are longer

Step-by-step explanation:

the planets days and nights length depends on its tilt and rotation speed. so it has nothing to do with that. A and C are wrong

the longer it takes to revolve around the sun the longer the year is, so its not B

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Enter the equation of the line meeting the given conditions. Please put the equation instandard form.
just olya [345]

first, the slope is needed, which is 3-2/3--3 which is 1/6 and so this will be y=(1/6)x+b which then we'll input (3,3) which is 3=2+b or b=1 so the equation is y=(1/6)x+1

6 0
3 years ago
A jar contains 45 red candies and 60 black candies. Suppose a candy is selected at random. What are the odds against selecting a
uysha [10]

Answer:

3:4.

Step-by-step explanation:

To work this out we need to find the highest multiple of 45 and 60.

15 is the largest number that goes into both of them so what we are going to do now is divide both number by 15.

45 divided by 15 = 3

60 divided by 15 = 4

Therefore the odds of selecting a red candy is 3:4.

Hope that helps. x

7 0
3 years ago
BRAINLIEST FOR RIGHT ANSWER!!
julsineya [31]

Answer: {\boxed{h(x+4)=\frac{9+3x}{8+x}}}

Concept:

In a function f(x), it represents a function in terms of x or for x. Therefore, to find the values in the function, substitute values within the parenthesis to solve.

Solve:

<u>Given information</u>

h(x)=\frac{-3+3x}{4+x}

<u>Need to find</u>

h(x+4)

<u>Substitute (x + 4) to the position of x</u>

h(x+4)=\frac{-3+3(x+4)}{4+(x+4)}

<u>Distributive property on the numerator</u>

h(x+4)=\frac{-3+3x+12}{4+(x+4)}

<u>Combine like terms</u>

h(x+4)=\frac{-3+12+3x}{4+4+x}

\boxed{h(x+4)=\frac{9+3x}{8+x}}

Hope this helps!! :)

Please let me know if you have any questions

5 0
2 years ago
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