In the given figure triangle ABC, AC=100, CB= 50 , then find the value of x?
1 answer:
Step-by-step explanation:
Given that
∆ABC is a right angled triangle
angle B = 90°
BC = 50 units
Hypotenuse (H) = AC
AC = 100 units
We know that
Cos A = Adjacent side to angle A / Hypotenuse
→Cos x = BC / AC
→Cos x = 50/100
→Cos x = 1/2
→Cos x = Cos 60°
.°. x = 60°
Hence, the value of “x” is 60°
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Points B, D, and F are midpoints of the sides of triangle ACE. EC = 38 and DF = 16. Find AC. The diagram is not to scale. For my answer I put 32 because df is p...
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Answer:
The speed of Dave is 42 miles per hour
The speed of Kent is 46 miles per hour .
Step-by-step explanation:
Given as :
The distance cover by Dave = d = 210 miles
The time taken by Dave = t hour
The speed of Dave = s miph
<u>Again</u>
The distance cover by Kent = D = 230 miles
The time taken by Kent = T hour
The speed of Kent = S = (s + 4 ) miph
<u>For Dave</u>
Time =
So, t =
Or, t =
<u>For Kent</u>
Time =
So, T =
Or, T =
∵ Time taken by both is same
So, t = T
Or, =
Or, 210 × (s + 4) = 230 × s
Or, 210 × s + 210 × 4 = 230 × s
Or, 210 × 4 = 230 × s -210 × s
Or, 210 × 4 = 20 × s
∴ s =
i.e s = 42 miph
So, The speed of Dave = s = 42 miles per hour
Again
The speed of Kent = S = (s + 4 ) miph
i.e S = 42 + 4
or, S = 46 miph
So, The speed of Kent = S = 46 miles per hour
Hence,The speed of Dave is 42 miles per hour
And The speed of Kent is 46 miles per hour . Answer