Step-by-step explanation:
Lets assume that angle of right angle trangles are <a,<b and <c
here one of the angle is 90°
so, <a=90°
now,
By the question
<c=3×<b+14
again,
<a+<b+<c=180° (being sum of interior angles of trangles)
90°+<b+(3×<b+14)=180° ( including the value of <a and <c)
90°+<b+3<b+14=180°
4<b=180-90-14
<b=86/4
<b=19°
<c=3×<b+14
=3×19+14
<c=71
smallest angle is 19°
and another small angle is 71°
A parallel line has the same slope as the original line. So in this case the slope of the line is also 3/4. Now how do we know if it intersects the point? We need to adjust the y intercept.
Currently, we know the equation of the line is y= 3/4 x + b, where b is the thing we are looking for. We also have a point, which supplies the x and y. Plug that in and solve for b
-2 = (3/4)*(12) + b
You'll get b= -11
So the equation of the parallel line intersecting the point given is y= 3/4x -11.
I am assuming that the slope is 3/4 based on the way you formatted the original equation, but it's the same steps if the slope is different.
Answer:
11
Step-by-step explanation:
apply pythagoras theorem