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vredina [299]
3 years ago
10

Find the Area of the shape | help me this is due tomorrow!]

Mathematics
1 answer:
JulsSmile [24]3 years ago
7 0

Answer:

( 3 \pi ) unit²

Step-by-step explanation:

You might be interested in
Find the equation of the line through point (10,4) and parallel to 3x+5y=8.
Gnom [1K]
Parallel = same slope
Find slope of 3x + 5y = 8
Turn into y = mx + b
5y = -3x + 8
Divide by 5
y = -3/5x + 8/5
Slope is -3/5
Y = -3/5x + b, find y intercept
Plug in the point
4 = -3/5(10) + b
4 = -6 + b, b = 10
Final equation: y = -3/5x + 10
8 0
3 years ago
Quadrilateral PUMA has coordinates at P(-5,-2), U(-1,2), M(4,-3), A(0,-7) and it is transformed by (x+3,y-5). Determined the ima
IgorLugansk [536]

The image of M is (7 , -8)

Step-by-step explanation:

Let us revise some transformation

  • If the point (x , y) translated horizontally to the right by h units  then its image is (x + h , y)
  • If the point (x , y) translated horizontally to the left by h units  then its image is (x - h , y)
  • If the point (x , y) translated vertically up by k units  then its image is (x , y + k)
  • If the point (x , y) translated vertically down by k units  then its image is (x , y - k)

∵ The quadrilateral PUMA has coordinates at:

   P (-5 , -2) , U (-1 , 2) , M (4 , -3) , A (0 , -7)

∵ It is transformed by (x + 3 , y - 5)

- That means the quadrilateral translated 3 units right and 5 units

   down, then we add each x-coordinate by 3 and subtract 5 from

   each y-coordinate

∵ The coordinates of point M are (4 , -3)

∴ The image of point M = (4 + 3 , -3 - 5)

∴ The image of point M = (7 , -8)

The image of M is (7 , -8)

Learn more:

You can learn more about transformation in brainly.com/question/5563823

brainly.com/question/11203617

*LearnwithBrainly

8 0
3 years ago
What is the slope of (5,5) and (0,1)​
irina1246 [14]

Answer:

4/5

Step-by-step explanation:

Use the formulae

y2-y1 divided by x2- x1 then you will get your slope

3 0
3 years ago
This figure is made up of a quadrilateral and a semicircle.
Arturiano [62]

Answer:

The correct option is B. The area of the figure is 40.4 units².

Step-by-step explanation:

The line AB divides the figure in two parts one is a rectangle and another is semicircle.

The distance formula is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

The length of AB is

AB=\sqrt{(2+3)^2+(4-2)^2}=\sqrt{25+4}=\sqrt{29}

The length of AD is

AD=\sqrt{(-1+3)^2+(-3-2)^2}=\sqrt{4+25}=\sqrt{29}

Since AB=AD, therefore ABCD is a square. The area of the of square is

A_1=a\times a=\sqrt{29}\times \sqrt{29} =29

The area of square is 29 units².

The area of a semicircle is

A_2=\frac{\pi}{2}r^2

Since AB is the diameter of the semicircle, therefore the radius of the semicircle is

r=\frac{d}{2}=\frac{\sqrt{29}}{2}

The area of the semicircle is

A_2=\frac{3.14}{2}(\frac{\sqrt{29}}{2})^2=40.3825

The area of the figure is

A=A_1+A_2=29+11.2825=40.3825\approx 40.4

Therefore the area of the figure is 40.4 units². Option B is correct.

5 0
4 years ago
Find the LCM of 6 and 8 and list the multiples <br>​
Hitman42 [59]

Answer:

24

Step-by-step explanation:

6x4

8x3

8 0
3 years ago
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