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3 years ago

Given a circle wirh a circumference of 33 cm, find the radius.

1 answer:

5 0

To find the diameter of a circle using only the circumference, you need to use this formula: d=C/<span>π </span><span>

so it should go like:

d=33/3.14
</span>
d=10.51

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Find an equation for the line that passes through the point (-4, 10) and (16, -2)

Crank

Answer:

y = 3/5x + 62/5

Step-by-step explanation:

Equation of a line with two points is

m = y - y_1 / x - x _1

m = y_2 - y_1 / x_2 - x _1

Equating both

y - y_1 / x - x_1 = y_2 - y_1 / x_2 - x_1

Using what we are provided with

(-4 , 10)(16 , -2)

x_1 = -4

y_1 = 40

x_2 = 16

y_2 = -2

Imputing the values

10 - (-2) / 16 - (-4) = y - 10 / x - (-4)

10 + 2 /16 + 4 = y - 10 / x + 4

12 / 20 = y - 10 / x + 4

Lets cross multiply

12 ( x + 4) = 20(y - 10)

Open the brackets

12x + 48 = 20y - 200

12x + 48 + 200 = 20y

12x + 248 = 20y

Following this equation of line

y = mx + C

20y = 12x + 248

Let's divide through by 20 to get y.

20y / 20 = 12x + 248 / 20

y = 12x + 248 / 20

We can separate it by

y = 12x / 20 + 248 / 20

y = 3/5x + 62/5

Therefore, the equation of the line is

y = 3/5x + 62/5

3 0

3 years ago

The area of a square in square feet is

Sedaia [141]

Answer:

Part 1) The expression for the perimeter is $P=4(25z-3)$ or $P=100z-12$

Part 2) The perimeter when z = 15 ft. is $P=1,488\ ft$

Step-by-step explanation:

Part 1)

we have

$625z^{2}-150z+9$

Find the roots of the quadratic equation

Equate the equation to zero

$625z^{2}-150z+9=0$

Complete the square

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$625z^{2}-150z=-9$

Factor the leading coefficient

$625(z^{2}-(150/625)z)=-9$

$625(z^{2}-(6/25)z)=-9$

Complete the square. Remember to balance the equation by adding the same constants to each side

$625(z^{2}-(6/25)z+(36/2,500))=-9+(36/4)$

$625(z^{2}-(6/25)z+(36/2,500))=0$

Rewrite as perfect squares

$625(z-6/50)^{2}=0$

$z=6/50=0.12$ -----> root with multiplicity 2

The area is equal to

$A=625(z-0.12)(z-0.12)=[25(z-0.12)][25(z-0.12)]=(25z-3)^{2}$

The length side of the square is $b=(25z-3)$

therefore

The perimeter is equal to

$P=4b$

$P=4(25z-3)$

$P=100z-12$

Part 2) Find the perimeter when z = 15 ft.

we have

$P=100z-12$

substitute the value of z

$P=100(15)-12=1,488\ ft$

4 0

3 years ago

Type the correct answer in each box, Spell all words correctly, and use numerals instead of words for numbers. If necessary, use

SpyIntel [72]

Given function:

$f(x)=4 x^{3}=c$

To find:

The input if the output is 32.

The output if the input is 4.

Solution:

Input is x and output is c.

Substitute c = 32 in f(x).

$4 x^{3}=32$

Divide by 4 on both sides, we get

$x^{3}=8$

$x^{3}=2^3$

Taking cube root on both sides.

$x=2$

The input is 2 if the output is 32.

Substitute x = 4 in f(x).

$4 (4)^{3}=c$

$4 (64)=c$

$256=c$

The output is 256 if the input is 4.

6 0

3 years ago

Read 2 more answers

Ryan has scored 64, 75, 69, 58, and 63 on his previous five tests. What score does he need on his next test so that his average

ser-zykov [4K]

Answer:

Step-by-step explanation:

8 0

2 years ago

Calculate 8.694 times 10 to the power of 2 ( standard form) plz helpppp

qaws [65]

Answer:sheep

Step-by-step explanation:

5 0

3 years ago