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seraphim [82]
3 years ago
8

Type the correct answer in each box, Spell all words correctly, and use numerals instead of words for numbers. If necessary, use

/ for
the fraction bars)
The function below has an input, x, and produces a specific output c. f(x)=4x^3=c

Mathematics
2 answers:
SpyIntel [72]3 years ago
6 0

Given function:

f(x)=4 x^{3}=c

To find:

The input if the output is 32.

The output if the input is 4.

Solution:

Input is x and output is c.

Substitute c = 32 in f(x).

4 x^{3}=32

Divide by 4 on both sides, we get

x^{3}=8

x^{3}=2^3

Taking cube root on both sides.

x=2

The input is 2 if the output is 32.

Substitute x = 4 in f(x).

4 (4)^{3}=c

4 (64)=c

256=c

The output is 256 if the input is 4.

34kurt3 years ago
5 0

Answer:

So, x = [(1/4)c]1/3

input is 2 if the output is 32

output is 256 if the input is 4

Step-by-step explanation:

answer

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3 years ago
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Answer:

1.6y+y-4/15y+7/6y=21/3

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1.6y+y-4/15y+7/6y-(21/3)=0

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y∈R

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We add all the numbers together, and all the variables

1.6y+y-4/15y+7/6y-7=0

We add all the numbers together, and all the variables

2.6y-4/15y+7/6y-7=0

We calculate fractions

2.6y+(-24y)/90y^2+105y/90y^2-7=0

We multiply all the terms by the denominator

(2.6y)*90y^2+(-24y)+105y-7*90y^2=0

We add all the numbers together, and all the variables

(+2.6y)*90y^2+(-24y)+105y-7*90y^2=0

We add all the numbers together, and all the variables

105y+(+2.6y)*90y^2+(-24y)-7*90y^2=0

Wy multiply elements

-630y^2+105y+(+2.6y)*90y^2+(-24y)=0

We get rid of parentheses

-630y^2+105y+(+2.6y)*90y^2-24y=0

We add all the numbers together, and all the variables

-630y^2+81y+(+2.6y)*90y^2=0

Step-by-step explanation:

5 0
3 years ago
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