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Galina-37 [17]
3 years ago
5

A triangle has sides with lengths of 4 inches, 8 inches, and 9 inches. Is it a right triangle?

Mathematics
2 answers:
olasank [31]3 years ago
7 0

Answer:

\boxed {\boxed {\sf No,  \ not  \ a \  right \ triangle}}

Step-by-step explanation:

If a triangle is a right triangle, it will satisfy Pythagorean's Theorem.

a^2+b^2=c^2

When <em>a </em>and <em>b </em>are the legs of the triangle and <em>c</em> is the hypotenuse.

4 and 8 would be the legs of the triangle. 9 would be the hypotenuse because it is the longest side.

(4)^2 + (8)^2 = (9)^2

Solve the exponents.

16+64=81

Add on the left side of the equation.

80=81\\80 \neq 81

80 is not equal to 81. The triangle does not satisfy Pythagorean's Theorem, so it cannot be a right triangle.

Inga [223]3 years ago
4 0

Answer:

No, its not a right triangle

Step-by-step explanation:

4^{2} +8^{2} =9^{2}

16 + 64 = 81

80 = 81

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\displaystyle\frac{x - 27293}{7235} = 0.524\\\\x = 31084.14  

The 70th percentile for the distribution of college cost is $31,084.14

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