Question

A triangle has sides with lengths of 4 inches, 8 inches, and 9 inches. Is it a right triangle?

Answer 1

Answer:

$\boxed {\boxed {\sf No, \ not \ a \ right \ triangle}}$

Step-by-step explanation:

If a triangle is a right triangle, it will satisfy Pythagorean's Theorem.

$a^2+b^2=c^2$

When a and b are the legs of the triangle and c is the hypotenuse.

4 and 8 would be the legs of the triangle. 9 would be the hypotenuse because it is the longest side.

$(4)^2 + (8)^2 = (9)^2$

Solve the exponents.

$16+64=81$

Add on the left side of the equation.

$80=81\\80 \neq 81$

80 is not equal to 81. The triangle does not satisfy Pythagorean's Theorem, so it cannot be a right triangle.

Answer 2

Answer:

No, its not a right triangle

Step-by-step explanation:

$4^{2} +8^{2} =9^{2}$

16 + 64 = 81

80 = 81