I think I have the diagram right.
Let ADB = x, and then BDC = x+32.
x+x+32 = 90
2x = 58
x = 29 = ADB
so BDC = 61
Answer:
(-19, 55)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -3x - 2
5x + 2y = 15
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em>: 5x + 2(-3x - 2) = 15
- Distribute 2: 5x - 6x - 4 = 15
- Combine like terms: -x - 4 = 15
- Isolate <em>x</em> term: -x = 19
- Isolate <em>x</em>: x = -19
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: y = -3x - 2
- Substitute in <em>x</em>: y = -3(-19) - 2
- Multiply: y = 57 - 2
- Subtract: y = 55
100 because that just isn’t possible
I hope this helps.....
Explanation:
I took this in 9th grade so I know how to do this kind of stuff
Answer:
-33/4 or -8 1/4
Step-by-step explanation:
Make similar terms:
-5/4 - 28/4: then solve
-5 - 28 = -33: put over 4
-33/4: simplify
-8 1/4
