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dybincka [34]
2 years ago
8

A nurse gave an 8 year old child a dose of 6 mL of medicine. What would be the adult equivalent of this dosage

Mathematics
1 answer:
aleksley [76]2 years ago
3 0
Ok read first heheheh where
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Solve for x (please help i dont know how to this one ;-;)
Orlov [11]
Use this app is the best app ever

8 0
2 years ago
The heights (in cm) and arm spans (in cm) of 31 students were measured. The association between (height) and (arm span) is shown
sergeinik [125]

Answer: Mike's arm span is 7.165 cm longer than the George's one.

Step-by-step explanation:

We have that the association between height and arm span is modeled by the equation

y = 4.5 + 0.977*x

where y is height and x is arm span.

Mike is 172 cm tall, so his arm span is:

172cm = 4.5 + 0.977*x

x = (172 - 4.5)/0.977 = 171.443 cm

and George is 165 cm tall, so his arm span is:

x = (165 - 4.5)/0.977 = 164.278 cm

Then the difference between their arm span is:

171.443cm - 164.278cm = 7.165 cm

So Mike's arm span is 7.165 cm longer than the George's one.

6 0
3 years ago
Which shows the given inequalities in slope-intercept form?
yanalaym [24]

Answer: Solve for X      

4x−5y<1

Step-by-step explanation:

step 1 add 5y to each side

4x−5y+5y<1+5y

4x<5y+1

Step 2: Divide both sides by 4.

4x4<5y+14

x<54y+14

Answer:

x<54y+14

Let's solve for x.

12y−x<3

Step 1: Add (-1)/2y to both sides.

−x+12y+−12y<3+−12y

−x<−12y+3

Step 2: Divide both sides by -1.

−x−1<−12y+3−1

x>12y−3

Answer:

x>12y−3

now just graph 4x-5y<1 shows the given inequalities in slope -intercep form.

4 0
3 years ago
Can I have some help I’ll mark brainliest
Juli2301 [7.4K]
45/45/90 triangle has side ratios s/s/sroot2
leg = root 5
Other leg is also root 5
X is Hypotenuse which would be root 5 * root 2
root 5*2 = root 10
6 0
2 years ago
What is the vertex form of Y = x2 - 6x + 6?
ahrayia [7]

Answer:

\large\boxed{y=(x-3)^2-3}

Step-by-step explanation:

The vertex form of a quadratic equation <em>y = ax² + bx + c:</em>

<em>y = a(x - h)² + k</em>

(h, k) - coordinates of a vertex

We have the equation <em>y = x² - 6x + 6</em>.

Convert to the vertex form:

y=x^2-2(x)(3)+6\\\\y=\underbrace{x^2-2(x)(3)+3^2}_{(*)}-3^2+6\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\qquad(*)\\\\y=(x-3)^2-9+6\\\\y=(x-3)^2-3\to h=3,\ k=-3

7 0
2 years ago
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