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3 years ago

What is the value of 2 1/5 +3 4/5=

Mathematics

1 answer:

navik [9.2K]3 years ago

5 0

Answer:

Step-by-step explanation:

I like to line up my addition problems vertically

2 1/5

+ 3 4/5

--------------

5 5/5

but 5/5 = 1

5 + 1

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Find the area of the rhombus

professor190 [17]

Answer:

108

Step-by-step explanation:

none. I looked it up...so ion know lol. Im just tryna get these 50 points for sum reason...

3 0

3 years ago

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Find the percent of decrease from 340 to 260. Round to the nearest tenth of a percent, if necessary. A.) 23.5% B.) 130.8% C.) 30

Ad libitum [116K]

Answer: A) 23.5%
Explanation: 340-260= 80
80/340=0.2352x100=23.5

3 0

3 years ago

Use back-substitution to solve the system of linear equations.

ludmilkaskok [199]

Step-by-step explanation:

x - y + 5z = 29

y + 2z = 4

z = 7

since z = 7 we can use this value in second equation

y + 2×7 = 4 and y = -10

now we know the value of y we can solve the first equation

x -(-10) + 5×7 = 29

x + 10 + 35 = 29

x = -11

5 0

3 years ago

Read 2 more answers

Find the quotient.<br> 52.06 divided by 1.9

Grace [21]

Answer:

27.4

Step-by-step explanation:

First multiply the numerator and denominator by 10

Then write the problem in long division format

Then divide 52 by 19 and get 2

Then multiply the quotient digit (2) by the divisor 19

Then subtract 38 from 52

Then bring down the next number of the dividend

Then divide 140 by 19 to get 7

Then multiply the quotient digit (7) by the divisor 19

Then subtract 133 from 140

Then add a decimal point to the solution

Then bring down the next number of the dividend

Then divide 76 by 19 to get 4

Then multiply the quotient digit (4) by the divisor 19

Then subtract 76 from 76

The solution for long division for 52.06./1.9 is 27.4

27.4

7 0

3 years ago

Read 2 more answers

What are the solutions to the following system?

bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

$y=-3 x^{2}+5$ (given) -------- (2)

Equate (1) and (2).

$-5+2 x^{2}=-3 x^{2}+5$

Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

$-5+5x^{2}=5$

Add 5 on both sides.

$-5+5x^{2}+5=5+5$

$5x^{2}=10$

Divide by 5 on both sides, we get

$x^{2}=2$

Taking square root on both sides, we get

$x=\sqrt{2}, x=-\sqrt{2}$

Substitute $x=\sqrt{2}$ in (1).

$y=-5+2(\sqrt{2})^2$

$y=-5+4$

$y=-1$

Substitute $x=-\sqrt{2}$ in (1).

$y=-5+2(-\sqrt{2})^2$

$y=-5+4$

$y=-1$

Therefore the solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Option C is the correct answer.

6 0

3 years ago