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krek1111 [17]
3 years ago
10

A train leaves Buffalo traveling west at 60 miles per hour. An hour later, another train leaves Buffalo traveling east at 80 mil

es per hour. When are the two trains the same distance from Buffalo? Show the equation you use and solve it.
Mathematics
1 answer:
kozerog [31]3 years ago
8 0
The two trains the same distance from Buffalo is 20
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The math club sells candy bars an d drinks during football games. • 60 candy bars and 110 drinks will sell for $265. • 120 candy
Sedbober [7]
We can set up a system of equations to solve this. 

120b + 90d = 270
60b + 110d = 265

To cancel out b, first make the b terms equal.

60b · 2 + 110d · 2 = 265 · 2
120b + 220d = 530

Now subtract the equations.

 120b +   90d =  270
-120b + 220d =  530
---------------------------
            -130d = -260

Solve for d.

-130d/-130 = -260/-130
d = 2

Now put the value of d in one of the equations. 

60b + 110d = 265
60b + 110 · 2 = 265
60b + 220 = 265
60b + 220 - 220 = 265 - 220
60b = 45
60b/60 = 45/60
b = 0.75

Each candy bar sells for $0.75

Hope this helps! :)
7 0
3 years ago
Problem Solving
N76 [4]

you're absolutely correct.

each system is sold for $2150, that includes cost + markup, namely the markup is the surplus amount otherwise called "profit".

they sold 12 of those, 2150 * 12 = 25800

they had $4824.36 in profits from it, so if we subtract that from the sale price, we'll be left with the cost of all 12 systems

25800 - 4824.36 = 20975.64

that's the cost for all 12 systems sold, how many times does 12 go into 20975.64?  20975.64 ÷ 12 = 1747.97.

7 0
2 years ago
Show that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).​
Len [333]

Step-by-step explanation:

1) if (0;0) if point A, (1;2) is point B; (-1;-2) is C, (2;1) is D, then

2) the vector AB is (1;2); vector AC is (-1;-2) and vector AD is (2;1), then

3) the length of AB, AC and AD are:

|AB|=\sqrt{1^2+2^2}=\sqrt{5};

|AC|=\sqrt{(-1)^2+(-2)^2}=\sqrt{5};

|AD|=\sqrt{2^2+1^2}=\sqrt{5}.

4) if the lengths above are equal, then it means that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).

3 0
2 years ago
Two sides of a triangle are as follows: 2 centimeters and 5 centimeters. Describe the possible lengths of the third side
Elden [556K]

Answer:

3cm < Third side < 7cm

Thus third side can take any value between 3cm and 7 cm

(note: excluding 3 cm and 7 cm)

If the value are integral then possible values of third side are

4cm, 5cm,6cm

Step-by-step explanation:

This question can be solved using given by Triangle Inequality Theorem Given below.

  • Sum of two sides is always greater than value of third side
  • Difference of two sides is always less than value of third side

Given two sides are 2cm, 5cm

Sum of two sides = (2+5)cm = 7 cm

Difference of two sides = (5-2) = 3 cm

Let the third side be X

thus according to Triangle Inequality Theorem

X <  Sum of two sides of given triangle

X < 7cm  -----1

X > Difference of two sides

X > 3cm  ----1

combining expression 1 and 2 we have

3cm < X < 7cm

Thus third side can take any value between 3cm and 7 cm

(note: excluding 3 cm and 7 cm)

If the value are integral then possible values are

4c, 5cm,6c

7 0
2 years ago
Find the percent of discount. Round to nearest tenth.
konstantin123 [22]
Your answer is 31% I believe. 
8 0
3 years ago
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