Rewrite the equations of the given boundary lines:
<em>y</em> = -<em>x</em> + 1 ==> <em>x</em> + <em>y</em> = 1
<em>y</em> = -<em>x</em> + 4 ==> <em>x</em> + <em>y</em> = 4
<em>y</em> = 2<em>x</em> + 2 ==> -2<em>x</em> + <em>y</em> = 2
<em>y</em> = 2<em>x</em> + 5 ==> -2<em>x</em> + <em>y</em> = 5
This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.
Compute the Jacobian determinant for this change of coordinates:

Rewrite the integrand:

The integral is then

9514 1404 393
Answer:
y = 0x + 15
Step-by-step explanation:
A line with a slope of 0 is a horizontal line. It has the same y-value everywhere. If it goes through the point (16, 15) with y-coordinate 15, then its y-intercept is 15.
Writing the slope explicitly, the equation is ...
y = 0x +15
Simplified, the equation is
y = 15
Answer:
x=2
Step-by-step explanation:
Answer:
line a
Step-by-step explanation:
line a is the answer