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Mashutka [201]
2 years ago
12

Find: (6m5 3 â€"" m3 â€"" 4m) â€"" (â€""m5 2m3 â€"" 4m 6) Write subtraction of a polynomial expression as addition of the additi

ve inverse. (6m5 3 â€"" m3 â€"" 4m) (m5 â€"" 2m3 4m â€"" 6) Rewrite terms that are subtracted as addition of the opposite. 6m5 3 (â€""m3) (â€""4m) m5 (â€""2m3) 4m (â€""6) Group like terms. [6m5 m5] [3 (â€""6)] [(â€""m3) (â€""2m3)] [(â€""4m) 4m] Combine like terms. Write the resulting polynomial in standard form. M5 â€"" m3 m â€"" 3.
Mathematics
1 answer:
aliina [53]2 years ago
3 0

The subtraction in the standard form of the polynomial is \rm 7m^5-3m^2-3.

Given that

Expression; \rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6).

We have to determine

The subtraction of a polynomial.

According to the question

Expression; \rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6).

To find the subtraction of the polynomial follow all the steps given below.

  • Step1; Write the expression as an additive inverse.

                   \rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)\\\\\rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)

  • Step2; Rewrite terms that are subtracted as the addition of the opposite.

        \rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)\\\\6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)

  • Step3; Group-like terms.

                   \rm 6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)\\\\(6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\

  • Step4; the resulting polynomial in standard form is,

                    \rm (6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\ 7m^5-3m^2-3

                   

Hence, the subtraction in the standard form of the polynomial is \rm 7m^5-3m^2-3.

To know more about Polynomial click the link given below.

brainly.com/question/26078031

                   

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Answer:

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Step-by-step explanation:

Let the required number be 100.

Now, according to the question, the number is first increased by 30 %

⇒ 100 + 30 % of 100

⇒ 100 + [(30*100)/100]

⇒ 100 + 30

⇒ 130

Then, it is decreased by 30 %

⇒ 130 - (30 % of 130)

⇒ 130 - [(30*130)/100]

⇒ 130 - 39

⇒ 91

Net Decrease = 100 - 91

= 9

Percent Decrease = (Change in number*100)/100

⇒ (9*100)/100

= 9 %

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Find the given higher-order derivative.<br><br> f''(x) = 9- 3/x<br><br> f'''(x)=
Genrish500 [490]

Answer:

f'''(x)=\frac{3}{x^{2}}

Step-by-step explanation:

We are given with Second-order derivative of function f(x).

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We need to find Third-order derivative of the function f(x).

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We know that,

f'''(x) = (f''(x))'

So,

f'''(x)=\frac{\mathrm{d}\,f''(x)}{\mathrm{d} x}

f'''(x)=\frac{\mathrm{d}\,(9-3x^{-1})}{\mathrm{d} x}

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