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1 year ago

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Find: (6m5 3 â€"" m3 â€"" 4m) â€"" (â€""m5 2m3 â€"" 4m 6) Write subtraction of a polynomial expression as addition of the additi

ve inverse. (6m5 3 â€"" m3 â€"" 4m) (m5 â€"" 2m3 4m â€"" 6) Rewrite terms that are subtracted as addition of the opposite. 6m5 3 (â€""m3) (â€""4m) m5 (â€""2m3) 4m (â€""6) Group like terms. [6m5 m5] [3 (â€""6)] [(â€""m3) (â€""2m3)] [(â€""4m) 4m] Combine like terms. Write the resulting polynomial in standard form. M5 â€"" m3 m â€"" 3.

1 answer:

aliina [53]1 year ago

3 0

The subtraction in the standard form of the polynomial is $\rm 7m^5-3m^2-3$ .

Given that

Expression; $\rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)$ .

We have to determine

The subtraction of a polynomial.

According to the question

Expression; $\rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)$ .

To find the subtraction of the polynomial follow all the steps given below.

Step1; Write the expression as an additive inverse.

$\rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)\\\\\rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)$

Step2; Rewrite terms that are subtracted as the addition of the opposite.

$\rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)\\\\6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)$

Step3; Group-like terms.

$\rm 6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)\\\\(6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\$

Step4; the resulting polynomial in standard form is,

$\rm (6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\ 7m^5-3m^2-3$

Hence, the subtraction in the standard form of the polynomial is $\rm 7m^5-3m^2-3$ .

To know more about Polynomial click the link given below.

brainly.com/question/26078031

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The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width

blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given perimeter

perimeter of rectangle = 2 ( length + width )

=> 30.8 km = 2 ( x + y )

=> $x + y = \frac{30.8}{2}$

=> y = 15.4 – x ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,

=> $length^2 + width^2 = diagonal^2$

=> $x^2 + y^2 = 11^2$

=> $x^2 + y^2 = 121$

On substituting value of y from (1) in above equation we get

=> $x^2 + (15.4-x)^2 = 121$

=> $x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x = 121$

=> $2x^2-30.8x + 237.16 -121 = 0$

=> $2x^2-30.8x + 116.16 = 0$

Solving above quadratic equation using quadratic formula

General form of quadratic equation is

$ax^2 +bx +c = 0$

And quadratic formula for getting roots of quadratic equation is

$x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}$

As equation is $2x^2-30.8x + 116.16 = 0$ , in our case

a = 2 , b = -30.8 and c = 116.16

Calculating roots of the equation we get

$x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}$

$x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}$

$x=\frac{30.8\pm\sqrt{860.64}}{4}$

$x=\frac{30.8\pm\sqrt{860.64}}{4}$

$x=\frac{(30.8\pm29.33)}4$

$x=\frac{(30.8+29.33)}{4}$

$x=\frac{(30.8-29.33)}{4}$

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

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2 years ago

Evaluate the expression 2b ^3+5 when b=3

pochemuha

Answer:

59

Step-by-step explanation:

b^3 is 27

2(27) is 54

54+5 is 59

if u mean (2b)^3 then 2b is 6

6^3 is 216

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2 years ago

Which of the following p values will lead us to reject the null hypothesis if the level of significance equals .05?

V125BC [204]

Answer:

So then our significance level is $\alpha=0.05$ and we need to remember these two conditions:

1) If the p value $p_v$ we have enough evidence to reject the null hypothesis at the significance level given

2) If the p value $p_v \geq \alpha$ we have enough evidence to FAIL reject the null hypothesis at the significance level given

And baed on the options we see that the only possibility would be:

d. 0.015

Step-by-step explanation:

We want to know for which value we would REJECT the null hypothesis.

So then our significance level is $\alpha=0.05$ and we need to remember these two conditions:

1) If the p value $p_v$ we have enough evidence to reject the null hypothesis at the significance level given

2) If the p value $p_v \geq \alpha$ we have enough evidence to FAIL reject the null hypothesis at the significance level given

And baed on the options we see that the only possibility would be:

d. 0.015

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2 years ago

The length of a new rectangular playing field is 5 yards longer than double the width. if the perimeter of the playing field is

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The answer is 59.6 because I divided 298 by 5
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2 years ago

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Answer:

No

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An irrational number is a number that never ends or repeats. This decimal ends and it doesn't repeat.

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2 years ago

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