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BigorU [14]
3 years ago
8

Please solve for n the following equation..............-2 = -n + 8

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
4 0

Answer:

n=-5

Step-by-step explanation:

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Which of the expressions (on the photo document I inserted) together represent all solutions to the following equation?
Ipatiy [6.2K]

Answer:

x =15 + 30n

Step-by-step explanation:

8cos(12x)+4=-4

Subtract 4 from each side

8cos(12x)+4-4=-4-4

8cos(12x)=-8

Divide by 8

8/8cos(12x)=-8/8

cos(12x) = -1

Take the arccos on each side

arccos(cos(12x)) = arccos(-1)

12x = 180 degrees  

But we can go around in a circle of 360 and get the same result

12 x = 180+360n  where n is an integer

Divide each side by 12

x = 180/12 +360n/12

x =15 + 30n

7 0
3 years ago
Suppose that 0.5% of all people have a disease. There is testing available for this disease. If the person being tested has the
Vlada [557]

Answer:

98%

Step-by-step explanation:

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3 years ago
PLEASE HELP ME! THERE IS A PICTURE
vichka [17]
B. 1/40…. You divide 1/2 by 20 to find out how much hand sanitizer was used on each desk. You can keep change flip meaning keep the 1/2 change the division to multiplication and flip the 20 to 1/20 then multiply. 1/2 by 1/20 which equals 1/40.
3 0
2 years ago
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There are 15 pieces of the same size candy in a bag. Four are banana flavored, three strawberry flavored, six cherry flavored, a
salantis [7]

Answer:

0.5

Step-by-step explanation:

There are 15 pieces of the same size candy in the bag. Two are orange flavored, six cherry flavored. So the probability of picking an orange or a cherry flavored candy is 6/15+2/15=8/15≈0.5

4 0
2 years ago
Before the distribution of certain statistical software, every fourth compact disk (CD) is testedfor accuracy. The testing proce
pishuonlain [190]

Answer:

P(T∩E) = 0.017

Step-by-step explanation:

Since every fourth CD is tested. Thus if T is the event that represents 4 disks being tested,

P(T) = 1/4 = 0.25

Let Fi represent event of failure rate. So from the question,

P(F1) = 0.01 ; P(F2) = 0.03 ; P(F3) =0.02 ; P(F4) = 0.01

Also Let F'i represent event of success rate. And we have;

P(F'1) = 1 - 0.01 = 0.99 ; P(F'2) = 1 - 0.03 = 0.97; P(F'3) = 1 - 0.02 = 0.98; P(F'4) = 1 - 0.01 = 0.99

Since all programs run independently, the probability that all programs will run successfully is;

P(All programs to run successfully) =

P(F'1) x P(F'2) x P(F'3) x P(F'4) =

0.99 x 0.97 x 0.98 x 0.97 = 0.932

Now, that all 4 programs failed will be = 1 - 0.932 = 0.068

Let E be denote that the CD fails the test. Thus P(E) = 0.068

Now, since testing and CD's defection are independent events, the probability that one CD was tested and failed will be =P(T∩E) = P(T) x P(E)= 0.25 x 0.068 = 0.017

8 0
3 years ago
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