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Fantom [35]
2 years ago
12

What is the answer for question 1 and how

Mathematics
2 answers:
Evgesh-ka [11]2 years ago
8 0
CAB= 180-42= 138/2= 69° as base angles of an isosceles triangle are equal
CAO= 90 as radius meets the tangent at 90°
OAB = 90-68= 21°
AOB= 180-(21+21)
=180-42= 138°
a²= b²+c²-2bcCosA
AB²= 7²+7²-2x7x7Cos138
AB²= 170.8281929
AB= √170.8281929
AB= 13.07012597cm
Or 13.1 to 3sf
quester [9]2 years ago
4 0

Step-by-step explanation:

ABC is an isoceles triangle (both legs are equally long). and AB is its baseline.

OC is now a median for ABC splitting the angle at C and AB in half.

so, we have 2 right-angled triangles : OAC and OBC.

the half-angles at C are 42/2 = 21°.

the angles at A and B are 90°.

and the half-angles at O are 180 - 90 - 21 = 69°.

remember that the sum of all angles in a triangle must always be 180°.

AB are the heights of both of these triangles.

the single height is sin(69)×7 = 6.535062985... cm

and so,

AB = 2× height = 13.07012597... cm.

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mariarad [96]
Length of a circle=2πr
r=40 m
Length of the circular track=2*π*40m=80π m.

The athelete jogs each day 10 laps
1 lap-------------------80π m
10 laps-------------   x
x=(10 laps * 80π m) / 1 lap=800π m

Calculate how far he jog eache week (5 days).
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5 days----------------   x
x=(5 days*800π m)/1day=4000π m=4000m * 3.141592...≈12566,37 m

solution: 12566 m

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3 years ago
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Billy's age= x

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3 years ago
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Hi, what exactly is the question ?
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3 years ago
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