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Fantom [35]
2 years ago
12

What is the answer for question 1 and how

Mathematics
2 answers:
Evgesh-ka [11]2 years ago
8 0
CAB= 180-42= 138/2= 69° as base angles of an isosceles triangle are equal
CAO= 90 as radius meets the tangent at 90°
OAB = 90-68= 21°
AOB= 180-(21+21)
=180-42= 138°
a²= b²+c²-2bcCosA
AB²= 7²+7²-2x7x7Cos138
AB²= 170.8281929
AB= √170.8281929
AB= 13.07012597cm
Or 13.1 to 3sf
quester [9]2 years ago
4 0

Step-by-step explanation:

ABC is an isoceles triangle (both legs are equally long). and AB is its baseline.

OC is now a median for ABC splitting the angle at C and AB in half.

so, we have 2 right-angled triangles : OAC and OBC.

the half-angles at C are 42/2 = 21°.

the angles at A and B are 90°.

and the half-angles at O are 180 - 90 - 21 = 69°.

remember that the sum of all angles in a triangle must always be 180°.

AB are the heights of both of these triangles.

the single height is sin(69)×7 = 6.535062985... cm

and so,

AB = 2× height = 13.07012597... cm.

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Answer:

Sin 29° 32' = Cos 60° 28'

Step-by-step explanation:

Here in this problem, we have to write Sin 29° 32' in terms of its co-function.

We know that co-function of Sin Ф = Cos ( 90° - Ф ).

Therefore, we have to find a complementary angle of 29° 32'.

So, ( 90° - 29° 32' ) = 60° 28'

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A recreation center is offering special prices on its pool passes and gym memberships for the summer. On the first day of the of
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Answer:

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The first equation shows two variables adding up to 3, so students choose a pair of values whose sum is 3. They notice that all pairs chosen are solutions to the system. Next, they try to find a strategy that can show that there are countless other pairs that also satisfy the constraints in the system. Monitor for these likely strategies:

Solving by graphing: The graphs of the two equations are the same line, so all the points on the line are solutions to the system.

Solving by substitution: The first equation can be rearranged to . Substituting for in the second equation gives or or . This equation is true no matter what is.

Solving by elimination: If we multiply the first equation by 4, rearrange the second equation to , and then subtract the second equation from the first, the result is . Subtracting from each side gives , which is true regardless of what or is.

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