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makvit [3.9K]
3 years ago
14

Question 20: Please help what are sin x and cos x?

Mathematics
1 answer:
sweet [91]3 years ago
8 0

Answer:

A is the correct answer.

Step-by-step explanation:

\tan x =   \frac{6}{8}  =  \frac{opposite \: side \: to \:  \angle \: x}{adjacent \: side \: to \:  \angle \: x}  \\  \\ hypotenuse  \\ =  \sqrt{ {(opp. \: side)}^{2} +  {(adj. \: side)}^{2}  }  \\  =  \sqrt{ {6}^{2} +  {8}^{2}  }  \\  =  \sqrt{36 + 64}  \\  =  \sqrt{100}  \\  = 10 \\  \\ \because  \sin (x) =  \frac{opposite \: side \: to \:  \angle \: x}{hypotenuse}  \\  \\   \huge{ \red{ \boxed{\therefore \: \sin (x) =  \frac{6}{10}}}}  \\  \\ \cos (x) =  \frac{adjacent \: side \: to \:  \angle \: x}{hypotenuse}  \\  \\  \huge{ \purple{ \boxed{\therefore \: \cos (x) =  \frac{8}{10} }}} \\

Thus, option A is the correct answer.

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