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3 years ago

How many moles are in 3.01x10^23 particles?

Chemistry

1 answer:

Romashka-Z-Leto [24]3 years ago

3 0

Answer:

.5 moles

Explanation:

in one mole there are 6.02x10^23 particles. 3.01x10^23 is one half of a mole

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If you want to measure a volume of 8 microliters that could be done with two different micropippetors (the 1-10 uL or 2-20 uL).

Soloha48 [4]

Hey There!

You should choose 1-10 uL pipette !

Small range measurement scales are more efficient than large range scale because they give more accurate measurement as they have visible marks on it small for all measurement.

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3 years ago

Calculate the number of joules of heat energy needed to increase the temperature of 25.0 g of metal from 21.0 ºC to 80.0 ºC. The

Harman [31]

Answer:

Q = 768.47 J

Explanation:

Given that,

Mass of the metal, m = 25 g

Initial temperature, T₁ = 21.0 ºC

Final temperature, T₂ = 80.0 ºC

The specific heat of the metal is 0.521 J/gºC.

We know that the heat released due to the change in temperature is given by :

$Q=mc\Delta T\\\\=25\times 0.521\times (80-21)\\Q=768.47\ J$

Hence, 768.47 J of heat energy will be needed.

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3 years ago

What does the arrangement of the periodic table help scientists see?

alexandr1967 [171]

option A is a precise one to be selected!

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3 years ago

Read 2 more answers

Balance the following skeleton reactions and identify the oxidizing and reducing agents:(b) P₄(s) → HPO₃²⁻(aq) + PH₃(g) [acidic]

m_a_m_a [10]

The balanced chemical equation is :

5P₄ + 36OH → 12HPO₃⁻² (aq) + 8PH₃ (acidic)

Here the oxidation number of P changed from 0 to -3 in PH₃ and increases from 0 to +3 in HPO₃⁻². When P₄ changes to PH₃ reduction reaction is taking place as there is addition of hydrogen and when P₄ changes to HPO₃⁻² oxidation takes place as there is addition of oxygen.

Thus clearly both reduction and oxidation are taking place.

Thus, we can infer that here P₄ is both oxidizing as well as reducing agent.

To know more about oxidation number here:

brainly.com/question/13182308

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2 years ago

Methyl red is a common acid-base indicator. it has a ka equal to 6.3 × 10–6. its un-ionized form is red and its anionic form is

Maksim231197 [3]

Hello!

The pKa of an indicator tells us the pH where it changes color. The pKa of Methyl red is

$pKa=-log(Ka)=-log( 6,3*10^{-6} )=5,20$

So, at a pH=7,8, Methyl Red would be at a pH over its pKa, so it would be in its basic form. The Basic Form of Methyl Red is Yellow, so the solution would be Yellow.

Have a nice day!

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3 years ago