Question

What is the equation of the line that passes through the point (3,2) and has a slope pf -5/3

Answer 1

Answer:

y=-5/3x+7

Step-by-step explanation:

y-y1=m(x-x1)

y-2=-5/3(x-3)

y=-5/3x+15/3+2

y=-5/3x+5+2

y=-5/3x+7