If you get this correct I'll give you brianlieat tyyyy!! :D

Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind

Gemiola [76]

Answer:

(a)

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

(b)

i.

$1\ girl = \{GBB, BBG, BGB\}$

$P(1\ girl) = 0.375$

ii.

$Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}$

$P(Atleast\ 2 \ girls) = 0.5$

iii.

$No\ girl = \{BBB\}$

$P(No\ girl) = 0.125$

Step-by-step explanation:

Given

$Children = 3$

$B = Boys$

$G = Girls$

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

$S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}$

And the number of elements are:

$n(S) = 8$

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

$1\ girl = \{GBB, BBG, BGB\}$

And the number of the list is;

$n(1\ girl) = 3$

The probability is calculated as;

$P(1\ girl) = \frac{n(1\ girl)}{n(S)}$

$P(1\ girl) = \frac{3}{8}$

$P(1\ girl) = 0.375$

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

$Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}$

And the number of the list is;

$n(Atleast\ 2 \ girls) = 4$

The probability is calculated as;

$P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}$

$P(Atleast\ 2 \ girls) = \frac{4}{8}$

$P(Atleast\ 2 \ girls) = 0.5$

Solving (biii) No girl

From the list of possible elements, we have:

$No\ girl = \{BBB\}$

And the number of the list is;

$n(No\ girl) = 1$

The probability is calculated as;

$P(No\ girl) = \frac{n(No\ girl)}{n(S)}$

$P(No\ girl) = \frac{1}{8}$

$P(No\ girl) = 0.125$

7 0

3 years ago

2.2.PS-8 Find the value of x when 6 - 4x = 6x - 8x + 8. The value of x is

Bess [88]

Answer:

X = -1

Step-by-step explanation:

6 - 4x = 6x - 8x + 8

-6. -6

-4x = -2x + 2

+2x. +2x

-2x = 2

divide both sides by -2

x = -1

6 0

2 years ago

F(x)=2x^2-5;find when f(x)=-7

Daniel [21]

Answer:

x=i or no solution exists depending on the user's grade

Step-by-step explanation:

f(x) = 2x^2-5

-7 = 2x^2-5

-2 = 2x^2, x^2=-1, x=i

6 0

2 years ago

Read 2 more answers

The graph of the quadratic function y=-x^2-2x+3 is shown below

Karolina [17]

Answer:

The axis of symmetry is at $x=-1$

The graph has an x-intercept at $(1,0)$

The graph has a vertex at $(-1,4)$

Step-by-step explanation:

we have

$y=-x^{2}-2x+3$

Statements

case 1) The graph has root at $3$ and $1$

The statement is False

Because, the roots of the quadratic equation are the values of x when the value of y is equal to zero (x-intercepts)

Observing the graph, the roots are at $-3$ and $1$

case 2) The axis of symmetry is at $x=-1$

The statement is True

Observing the graph, the vertex is the point $(-1,4)$

The axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

so

the equation of the axis of symmetry is $x=-1$

case 3) The graph has an x-intercept at $(1,0)$

The statement is True

see procedure case 1)

case 4) The graph has an y-intercept at $(-3,0)$

The statement is False

Because, the y-intercept is the value of y when the value of x is equal to zero

Observing the graph, the y-intercept is the point $(0,3)$

case 5) The graph has a relative minimum at $(-1,4)$

The statement is False

Because, is a vertical parabola open downward, therefore the vertex is a maximum

The point $(-1,4)$ represent the vertex of the parabola, so is a maximum

case 6) The graph has a vertex at $(-1,4)$

The statement is True

see the procedure case 5)

see the attached figure to better understand the problem

6 0

3 years ago

Read 2 more answers

4/7 - -3/5 step by step pls explain

lidiya [134]

Answer:

41/35

Step-by-step explanation:

Simplify the following:

4/7 + 3/5

Put 4/7 + 3/5 over the common denominator 35. 4/7 + 3/5 = (5×4)/35 + (7×3)/35:

(5×4)/35 + (7×3)/35

5×4 = 20:

20/35 + (7×3)/35

7×3 = 21:

20/35 + 21/35

20/35 + 21/35 = (20 + 21)/35:

(20 + 21)/35

| 2 | 1

+ | 2 | 0

| 4 | 1:

Answer: 41/35

5 0

3 years ago