Answer:72.70
Step-by-step explanation: long story short math
Answer:
both kinds of tickets are $5 each
Step-by-step explanation:
Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:
12s + 5c = 85 . . . . . revenue from the first day of sales
6s + 9c = 75 . . . . . . revenue from the second day of sales
Double the second equation and subtract the first to eliminate the s variable.
2(6s +9c) -(12s +5c) = 2(75) -(85)
13c = 65 . . . . . simplify
65/13 = c = 5 . . . . . divide by the coefficient of c
Substitute this value into either equation. Let's use the second one.
6s + 9·5 = 75
6s = 30 . . . . . . . subtract 45
30/6 = s = 5 . . . divide by the coefficient of s
The price of a senior ticket is $5; the price of a child ticket is $5.
Answer:
The equipment will cost $1740.
Step-by-step explanation:
Let the Cost of equipment, furniture and decoration be x, y and z.
Now, According to question,
x + y + z = 3600 ...... (1) (cost of all items)
x = 500 + y (∵ equipment cost 500 more than furniture)
and y = 2z ( ∵ furniture twice as much as decoration)
so, z = y/2
Now substituting the value of x and z in eq (1)
So, the cost of furniture (y) = 1240
∴ Cost of equipment = y + 500 = 1240 + 500 = 1740
Therefore the cost of equipment was $1740.
-58 is your answer.
17 - 75 = -58
I hope this helps!
