Question

5. A ball is thrown straight up leaving the player's hands at at 7.5 m/s. If air resistance is ignored, how high can the ball travel? Show all work starting with Ebefore = Eafter.

Answer 1

The maximum height reached is 2.87 meters

What is maximum height?

The maximum height of an object is the highest vertical position along the trajectory of the object.

The given parameters are:

• $u = 7.5ms^{-1}$ --- the initial velocity
• $v = 0ms^{-1}$ --- the final velocity
• $a =-g$ --- the acceleration

To calculate the height (s) of the ball, we make use of the following equation of motion:

$v^2 = u^2 + 2as$

Substitute known values

$0^2 = 7.5^2 - 2gs$

$0 = 56.25 - 2gs$

Collect like terms

$2gs = 56.25$

Substitute 9.8 for g

$2 \times 9.8 s = 56.25$

$19.6 s = 56.25$

Divide both sides by 19.6

$s = 2.87$

Hence, the maximum height reached is 2.87 meters

Read more about acceleration and maximum height at:

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