Answer: option D
Step-by-step explanation:
Remember the cosine identity:

Given the right triangle DFE shown in the image, you can identify that the adjacent side and the hypotenuse for the angle F of this triangle are:

Now you can substitute values into
and then reduce the fraction.
THerefore you get:
Answer:
B
Step-by-step explanation:
Start by breaking down the equation
-1/2 x 10 = -5
-1/2x1/4=-1/4
Then combine your answer
-5=1/8
Answer:
2x
Step-by-step explanation:
you take 3x-x you get 2x. then you take 2x_2x you get 0.then -x_3x you get 2x.you take 0+2x you get 2x that is the answer
Answer:
20 + 0.05x ≥ 65
Step-by-step explanation:
20 is by itself since thats what he earns extra per day.
Since he earns 0.05 per flyer, that means we are going to need a variable since we don't know how many flyers he passes. Let x be equal to that.
Since he wants to make at LEAST 65 we are going to use the greater than or equal to symbol since he doesn't want to make less than that.
20 + 0.05x ≥ 65
Best of Luck!
Answer:

![\sqrt[3]{0.95} \approx 0.9833](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.95%7D%20%5Capprox%200.9833)
![\sqrt[3]{1.1} \approx 1.0333](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1.1%7D%20%5Capprox%201.0333)
Step-by-step explanation:
Given the function: ![g(x)=\sqrt[3]{1+x}](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B1%2Bx%7D)
We are to determine the linear approximation of the function g(x) at a = 0.
Linear Approximating Polynomial,
a=0
![g(0)=\sqrt[3]{1+0}=1](https://tex.z-dn.net/?f=g%280%29%3D%5Csqrt%5B3%5D%7B1%2B0%7D%3D1)

Therefore:

(b)![\sqrt[3]{0.95}= \sqrt[3]{1-0.05}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.95%7D%3D%20%5Csqrt%5B3%5D%7B1-0.05%7D)
When x = - 0.05

![\sqrt[3]{0.95} \approx 0.9833](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B0.95%7D%20%5Capprox%200.9833)
(c)
(b)![\sqrt[3]{1.1}= \sqrt[3]{1+0.1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1.1%7D%3D%20%5Csqrt%5B3%5D%7B1%2B0.1%7D)
When x = 0.1

![\sqrt[3]{1.1} \approx 1.0333](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1.1%7D%20%5Capprox%201.0333)