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lorasvet [3.4K]

2 years ago

13

Thandi deposits 850 into a bank. the bank will pay a simple interest rate of 8% per year. how much money will Thandi get when sh

e withdraws all her money after five years

1 answer:

marusya05 [52]2 years ago

4 0

Answer:

1084.83932813 which you would round to 1085

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4x-2y=7<br> -3x+3y=10<br> Find the point of intersection of the equations

garri49 [273]

4x-2y=7 (1)
-3x+3y=10 (2)
3y= 3x+10
y= x+10/3 (3)
sub (3) into (1)
4x-2(x+10/3)=7
4x-2x-20/3=7
2x-20/3=7
+20/3 +20/3
2x= 41/3
x= (41/3) / 2
x= 41/6
sub x= 41/6 into (3)
y= 41/6+10/3
= 61/6

Therefore the point of intersection is (41/6, 61/6)

4 0

3 years ago

Read 2 more answers

100 points please help !!!! right answer only

DochEvi [55]

$864 {in}^{2}$

is the answer of the question

6 0

3 years ago

Select all of the fractions that are terminating decimals *<br> 3/8<br> 5/6<br> 4/5<br> 2/7<br> 3/4

Paraphin [41]

Yes to every single one except the 4/5
:)

4 0

3 years ago

3. Eric filled 3/4 buckets with sand. Then he filled

Sedbober [7]

Answer:

472 3/4

Step-by-step explanation:

Consider the meaning of "one, and one more". That does not mean zero (1-1). Rather, it means two (1+1).

__

Then 3/4 and 472 more is ...

$\dfrac{3}{4}+472=472\frac{3}{4}$

Eric has 472 3/4 buckets filled with sand.

_____

The problem statement here seems to be focused on the filled buckets, rather than the sand stockpile that Eric is working from. The amount in that stockpile is being reduced by the amount that is being used to fill buckets. In short, whether you add or subtract depends on what you're trying to figure.

5 0

3 years ago

Find the exact distance between the line 6x-y=-3 and the point (6,2). Show your work. Explain your answer.

timama [110]

Answer:

The distance between line 6 x - y = - 3 and point (6,2) is $\sqrt{37}$

Step-by-step explanation:

Given equation of line as :

6 x - y = - 3

And The points be ( 6 , 2 )

Let The distance between line and points = d

So , from point to line distance formula

d = $\frac{\begin{vmatrix}ax & + by & + c\end{vmatrix}}{\sqrt{a^{2}+b^{2}}}$

Or, d = $\frac{\begin{vmatrix}6x & - y & + 3\end{vmatrix}}{\sqrt{6^{2}+(-1)^{2}}}$

∵ points is ( 6 , 2 )

so, d = $\frac{\begin{vmatrix}6\times 6 & + (-1)\times 2 & + 2\end{vmatrix}}{\sqrt{6^{2}+(-1)^{2}}}$

or, d = $\frac{36-2+3}{\sqrt{37} }$

∴ d = $\frac{37}{\sqrt{37} }$

I.e d = $\sqrt{37}$

Hence The distance between line 6 x - y = - 3 and point (6,2) is $\sqrt{37}$ Answer

5 0

3 years ago