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wariber [46]
3 years ago
13

Consider the two expressions 5x + 2 and 5(x+2). (I’m sorry If the picture is unclear)

Mathematics
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

Step-by-step explanation:

x = 3                    5x + 2                 5(x+2)

                        = 5(3) + 2             = 5(3 + 2)

                        = 15 + 2                = 5(5)

                        = 17                      = 25

x = 6                    5x + 2                 5(x+2)

                        = 5(6) + 2             = 5(6 + 2)

                        = 30 + 2               = 5(8)

                        = 32                     = 40

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According to an​ airline, flights on a certain route are on time 80 ​% of the time. suppose 10 flights are randomly selected and
natulia [17]
<span>(a) This is a binomial experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
​(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
​(c) Fewer than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
​(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
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6 0
3 years ago
Solve: -5y- 9 = -(y - 1)
RoseWind [281]

Answer:

Exact Form:

y=-\frac{5}{2}

6 0
3 years ago
Read 2 more answers
Ashton used 12.6 gallons of gasoline to drive his car on a weekend trip. he averaged 21.5 miles per gallon. about how many miles
7nadin3 [17]

Answer: 270.9 miles.

Step-by-step explanation:

The formula  we use here is :

\text{Distance=Speed * Number of gallons of gasoline}

Given : Ashton used 12.6 gallons of gasoline to drive his car on a weekend trip. he averaged 21.5 miles per gallon.

Then \text{Distance traveled }=12.6\times21.5=270.9\text{ miles}

Hence, he traveled 270.9 miles.

4 0
3 years ago
A hair salon completed a survey of 367 customers about satisfaction with service(Dissatisfied, Neutral, Satisfied, or Very Satis
mamaluj [8]

The results of the survey are shown in the table.

It's required to calculate the following probabilities:

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The required probability is:

p=\frac{79}{367}

b) A customer is a walk-in

The first column labeled as 'Walk-in' has a total of 106 customers out of 367. The required probability is

p=\frac{106}{367}

c) A customer is dissatisfied and a walk-in.

We have to cross the row Dissatisfied with the column Walk-in. The number of customers that have both categories is 22 out of 367.

The required probability is:

p=\frac{22}{367}

d) A customer is very satisfied given he saw a TV ad.

This is a conditional probability, where the total is 111 because is the given condition. The customers that have both characteristics are 33, thus the required probability is:

p=\frac{33}{111}=\frac{11}{37}

e) A customer is satisfied or referred.

Total satisfied = 139

Total referred = 150

With both features = 62

Total customers with one or both features: 139 + 150 - 62 = 227

We have to subtract the common feature because it was counted twice.

The required probability is:

p=\frac{227}{367}

6 0
1 year ago
3. Which expression is equivalent to log532?
saul85 [17]

Answer: The Nth power xN of a number x was originally defined as x multiplied by itself, until there is a total of N identical factors. By means of various generalizations, the definition can be extended for any value of N that is any real number.

(2) The logarithm (to base 10) of any number x is defined as the power N such that

x = 10N

(3) Properties of logarithms:

(a) The logarithm of a product P.Q is the sum of the logarithms of the factors

log (PQ) = log P + log Q

(b) The logarithm of a quotient P / Q is the difference of the logarithms of the factors

log (P / Q) = log P – log Q

(c) The logarithm of a number P raised to power Q is Q.logP

log[PQ] = Q.logP

Step-by-step explanation:

8 0
3 years ago
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