Answer:
Step-by-step explanation:
<u>Step 1: Determine the area of the black area</u>
<u>Step 2: Determine the area of the entire white and black area</u>
<u>Step 3: Determine the difference to just get the white area</u>
Answer:
Answer:
Step-by-step explanation:
3y = -x + 6
y = -1/3x + 2
y - 3 = -1/3(x + 1)
y - 9/3 = -1/3x - 1/3
y = -1/3x + 8/3
first term = initial number
second term = initial number + common difference
third term = initial number + 2(common difference)
So...
2x+5-(x+4) = common difference
4x+3-(2x+5) = also common difference
2x+5-(x+4) = x+1
4x+3-(2x+5) = 2x-2
Because x+1=2x-2 we can solve for x.
x=3
So the sequence goes... 7,11,15...
19 is the fourth term
Answer:
Step-by-step explanation:
<u>Given</u>
(x -1)^2 +y^2 = 36
<u>Find</u>
the circle's center and radius
<u>Solution</u>
Compare the given equation to the standard form equation for a circle.
(x -h)^2 +(y -k)^2 = r^2 . . . . . . centered at (h, k) with radius r
This tells you ...
Your circle is centered at (1, 0) and has a radius of 6.
Problem:
find line perpendicular to 4x+7y+3=0 passing through (-2,1).
Solution:
We will first find the general form of the perpendicular line.
The perpendicular line has the form
7x-4y+k=0 .........................(1)
by switching the coefficients of x and y, and switching the sign of one of the two coefficients. This way, the slope of (1) multiplied by that of the original equation is -1, a condition that the two lines are perpendicular. The value of k is to be determined from the given point (-2,1).
To find k, we substitute x=-2, y=1 into equation (1) and solve for k.
7(-2)-4(1)+k=0
=>
k=14+4=18
Therefore the required line is
7x-4y+18=0
