Hello your correct answer would be 95.703
Have a great day if it is incorrect tell me in the comments
Answer:

Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by

where:
- f(t) is the remaining quantity of a substance after time t has elapsed.
- a is the initial quantity of this substance.
- T is the half-life
since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:

reduce fraction:

By using calculator we acquire:

hence, the remaining sample after 420 days is 0.625 kg
Assuming that this problem is asking about a cylinder, the volume can be found using the formula (pi)(r)^2 * h (area of the circle * height) and the surface area can be found using the formula (2)(pi)(r)h (circumference of the circle * height).
Volume = (pi)(16)^2 * 27 = 21,714.688 in^3
Surface Area = (2)(pi)(16) * 27 = 2,714.336 in^2
Answer:
-1ab^2 + 5b + 8
Step-by-step explanation:
3a^2+9ab+5-4a^2-4ab+3
3a^2-4ab^2=-1ab^2
9ab-4ab=5ab
5+3=8
-1ab^2+5ab+8
Answer:
You would expect the outcome to be void 240 times
Step-by-step explanation:
1000 x 0.24