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Agata [3.3K]
3 years ago
6

Solve the exponential equation: 2^10 = 4^2^x

Mathematics
1 answer:
arsen [322]3 years ago
3 0

Answer:

x = ln10/ln4

Step-by-step explanation:

2^10 = 4^2^x

Now, rewrite 4 with 2 as the base.

2^10 = 2^4^x

Now with rules of exponential equality, we can equal the powers on the left to the powers on the right as they both have the same base.

10 = 4^x

<em>using ln to lower the variable</em>, we get

ln10 = xln4

x = ln10/ln4

tadah!

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Let shirts is x and belt y
6x + 4y = 660
x = 3y
18y + 4y = 660 \\ 22y = 660 \\ y = 30 \\ x = 90
therfore
5(90) + 2(30) = 510
4 0
3 years ago
The table shows the scores that Ms. Cohen’s students earned on the Chapter 6 and Chapter 7 tests.
kow [346]
Answer: Third option: <span>the percentage of students who earned a score of “needs improvement” on the Chapter 6 test and a score of “proficient” on the Chapter 7 test.
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3 represents the number of <span>of students who earned a score of “needs improvement” on the Chapter 6 test.

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What is 14/25 as a percent
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6.974 rounded to The nearest tenth??? Can someone explain!!!!
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The data below gives the mean price (in cents) of a liter of regular gasoline at self-service filling stations at a sample of si
bogdanovich [222]

Answer:

135.05 ; 2.762 ; (133.201, 136.899) ; (132.840, 137.260)

Step-by-step explanation:

Given the data:

Urban area Price/liter

St. John, NL 137.1

Halifax 133.6

Montreal 136.2

Regina 132.3

Saskatoon 132.2

Yellowknife 138.9

Mean = (137.1 + 133.6 + 136.2 + 132.3 + 132.2 + 138.9) / 6

= 810.3 / 6

= 135.05

Standard deviation (σ) : √Σ(X - mean)²/n-1

(137.1 - 135.05)^2 + (133.6 - 135.05)^2 + (136.2 - 135.05)^2 + (132.3 - 135.05)^2 + (132.2 - 135.05)^2+ (138.9 - 135.05)^2 = 38.135

√(38.135 / (6 - 1))

= √7.627

= 2.7617023

= 2.762

C.)

90% confidence interval of the mean :

Mean ± Zcrit * σ/√n

Zcrit at 90% = 1.64

135.05 ± 1.64 * (2.762/√6)

135.05 ± 1.64 * 1.1275817

Lower Value = (135.05 - (1.64 * 1.1275817)) = 133.201

Upper Value = (135.05 + (1.64 * 1.1275817))) = 136.899

Confidence interval = (133.201, 136.899)

D.)

95% confidence interval of the mean :

Mean ± Zcrit * σ/√n

Zcrit at 95% = 1.96

135.05 ± 1.96 * (2.762/6)

135.05 ± 1.96 * 1.1275817

Lower Value = (135.05 - (1.96 * 1.1275817)) = 132.840

Upper Value = (135.05 + (1.96 * 1.1275817)) = 137.260

Confidence interval = (132.840, 137.260)

4 0
3 years ago
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