Expression = 5(3t+2)+7(2t+5)
=15t+10+14t+35
=29t+45 is the answer
Answer: The car has to sell for $20000
Step-by-step explanation:
Let x represent the price that the car would have to sell for in order for these two job opportunities to pay Jim the same amount.
Ace Cars says they will pay Jim a 10% commission on the sale price of each car. It means that his pay would be
10/100 × x = 0.1x
Budget Cars says they will pay him $500 per week plus a 7.5% commission on the sale price of each car. It means that his pay would be
500 + 0.075x
For boths pays to be the same, it means that
0.1x = 500 + 0.075x
0.1x - 0.075x = 500
0.025x = 500
x = 500/0.025
x = 20000
The car has to sell for $20000
Answer:
0.9999
Step-by-step explanation:
Let X be the random variable that measures the time that a switch will survive.
If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by
So, the probability that a switch fails in the first year is
Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.
Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and
where
equals combinations of 100 taken k at a time.
The probability that at most 15 fail during the first year is
Recall your d = rt, distance = rate * time
thus
![\bf \begin{array}{lccclll} &distance&rate&time(hrs)\\ &-----&-----&-----\\ \textit{first car}&d&55&x\\ \textit{second car}&380-d&75&x+1 \end{array}\\\\ -----------------------------\\\\ \begin{cases} \boxed{d}=(55)(x)\\\\ 380-d=(75)(x+1)\\ ----------\\ 380-\left( \boxed{(55)(x)} \right)=(75)(x+1) \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Blccclll%7D%0A%26distance%26rate%26time%28hrs%29%5C%5C%0A%26-----%26-----%26-----%5C%5C%0A%5Ctextit%7Bfirst%20car%7D%26d%2655%26x%5C%5C%0A%5Ctextit%7Bsecond%20car%7D%26380-d%2675%26x%2B1%0A%5Cend%7Barray%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%0A%5Cbegin%7Bcases%7D%0A%5Cboxed%7Bd%7D%3D%2855%29%28x%29%5C%5C%5C%5C%0A380-d%3D%2875%29%28x%2B1%29%5C%5C%0A----------%5C%5C%0A380-%5Cleft%28%20%5Cboxed%7B%2855%29%28x%29%7D%20%5Cright%29%3D%2875%29%28x%2B1%29%0A%5Cend%7Bcases%7D)
notice, the first car leaves at "x" time, the other leaves on hour later, or x + 1
the first car travels some distance "d", whatever that is, thus
the second car, picks up the slack, or the difference, they're 380 miles
apart, thus the difference is 380-d