we have
(a+b)(3a-b)(2a+7b)
step 1
Solve
apply distributive property
(a+b)(3a-b)=3a^2-ab-3ab-b^2=3a^2-4ab-b^2
step 2
Multiply (3a^2-4ab-b^2) by (2a+7b)
6a^3+21a^2b-8a^2b-28ab^2-2ab^2-7b^3=6a^3+13a^2b-30ab^2-7b^3
answer is
<h2>6a^3+13a^2b-30ab^2-7b^3</h2>
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Answer:
To reconcile we need to match the checkbook balance with that of the bank balance :
Checkbook balance :
Initial checkbook balance = $43676.09
Note collected = $2160.00 , Bank Service Charge = $15
Final Checkbook Balance = Initial balance + Note collected - Service charge
= 43676.09 + 2160 - 15
= $45821.09
Bank balance :
Initial Bank balance = $49668.90
Outstanding deposits = $8474.44 , Outstanding checks = $12322.25
Final Bank Balance = Initial balance - Outstanding checks + Outstanding deposits
= 49668.90 - 12322.25 + 8474.44
= $45821.09
So, both the checkbook balance and the bank balance are equal.
11 - 3m; m = 2 therefore
11 - 3 · 2 = 11 - 6 = 5
Answer: c. 5
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Answer: b. yx - 4
x = 6 and y = 2
2 · 6 - 4 = 12 - 4 = 8
