Can you solve this? Please ( 15+ points)

Mathematics

2 answers:

Vera_Pavlovna [14]2 years ago

6 0

Answer:

112+24x

Step-by-step explanation:

2(16+(10*4)+(x*12))

solve the inner bracket

2(16+40+12x)

solve this bracket

2(56+12x)

solve this now

112+24x

swat322 years ago

6 0

Answer:

$24x+112$

Step-by-step explanation:

First of all we will start with the brackets inside the equation,

1. $2[16+40+12x]$

Now we can multiply 2 by all the values inside the parentheses

2. $32+80+24x$

I just wanted to confirm that the big X is a variable?

Fact: Did you know that there are about 4 types of parenthese: ( ) - round brackets, [ ] - square brackets, { } - curly brackets, and < > - angle bracket.

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Read 2 more answers

Use synthetic division to determine whether the number k is an upper or lower bound (as specified for the real zeros of the func

mote1985 [20]

Solution:

The given Polynomial is :

$f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5})$

By Rational Root theorem the of Zeroes of the Polynopmial are:

$\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4$

But , $f(\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4)\neq 0$

So, no root of this polynomial is real.

Therefore, All the four roots of Polynomial are imaginary.

So, we can't say whether the number k=2, is an upper or lower bound of the polynomial $f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5})$ .