Which point is NOT part of the solution set?

What is the effect on the graph of the function f(x) = x^2 when f(x) is changed to f(x − 6)

olya-2409 [2.1K]

Answer:

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing $f(x) = x^2$ and $\:f\left(x\right)=\left(x-6\right)^2$ is represented as being shifted 6 units to the right as compare to the function $f(x) = x^2$ .

Step-by-step explanation:

When we Add or subtract a positive constant, let say c, to input x, it would be a horizontal shift.

For example:

Type of change Effect on y = f(x)

$y = f(x - c)$ horizontal shift: c units to right

So

Considering the function

$f(x) = x^2$

The graph is shown below. The first figure is representing $f(x) = x^2$ .

Now, considering the function

$\:f\left(x\right)=\left(x-6\right)^2$

According to the rule, as we have discussed above, as a positive constant 6 is added to the input, so there is a horizontal shift, 6 units to the right.

The graph of $\:f\left(x-6\right)=\left(x-6\right)^2$ is shown below in second figure. It is clear that the graph of $\:f\left(x-6\right)=\left(x-6\right)^2$ is shifted 6 units to the right as compare to the function $f(x) = x^2$ .

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing $f(x) = x^2$ and $\:f\left(x\right)=\left(x-6\right)^2$ is represented as being shifted 6 units to the right as compare to the function $f(x) = x^2$ .

5 0

3 years ago

Some one please help me this is my final question i think i have the right answers but im not sure

Xelga [282]

Asked and answered elsewhere.
brainly.com/question/9436435

3 0

3 years ago

find the mean, median, and mode of the data set round to the nearest tenth 15, 1 , 4, 4, 8, 7, 15, 4, 5

Dmitriy789 [7]

$15,\ 1,\ 4,\ 4,\ 8,\ 7,\ 15,\ 4,\ 15,\ 4,\ 5\to\underbrace{1,\ 4,\ 4,\ 4,\ 4,\ 5,\ 7,\ 8,\ 15,\ 15,\ 15}_{11}\\\\mean=\dfrac{1+4+4+4+4+5+7+8+15+15+15}{11}=\dfrac{82}{11}\approx7.5\\\\median:1,\ 4,\ 4,\ 4,\ 4,\ \boxed{5},\ 7,\ 8,\ 15,\ 15,\ 15\\\\mode:1,\ \underbrace{4,\ 4,\ 4,\ 4}_{4},\ 5,\ 7,\ 8,\ 15,\ 15,\ 15$

<h3>Answer: mean = 7.5, median = 5, mode = 4</h3>