Answer:
The central dogma of the molecular biology explains the flow of information from the replication of the DNA to the expression of proteins. This central dogma must be error free so that correct information can be transferred. The error in this process can cause life threatening situation. So, the phases of proof reading and rectification is required in this process.
From the DNA replication to the transcription of the RNA and final translation into the proteins requires proof reading mechanisms and many enzymes with the non enzymatic processes. The enzymes of transcription, replication and translation shows high degree of proof reading and works in efficient way. The incorporation of the amino acids, post translation modification makes the information flow as correct as possible.
Answer:
The average atomic mass (sometimes called atomic weight) of an element is the weighted average mass of the atoms in a naturally occurring sample of the element.
Explanation:
please give me a heart. anyone good at math just posted my question
The whiff of the perfume of Tammy reached the nostrils of Jim through the process of diffusion. The process of diffusion can be defined as the process by which the substances (liquid and gases) move from one place to another from the area of high concentration to the area of lower concentration. The particles of the perfume move from the Tammy's body (high concentration) towards Jim through the air (low concentration).
Hence, the answer is 'Option B - diffusion'.
Answer:
The correct genotype of the two pure lines and the F1 is:
A⁺A⁺B⁰B⁰C⁰C⁰D⁰D⁰ and A⁰A⁰B⁺B⁺C⁺C⁺D⁺D⁺
The number of additive alleles on each genotype are two and six respectively.
Explanation:
Locus( plural form . loci) are fixed point on a chromosome in which genes are located. These genes are specific genetic material or genotype.
Now;
If we decide to designate the allele of the four loci into either additive (⁺) or non-additive(⁰); we have the following :
Let's the allele of the four loci to be
A⁺/A⁰, B⁺/B⁰, C⁺/C⁰ and D⁺/D⁰
However, from the diagram below; we deduce that the correct genotype for the two pure lines and the F1 is as follows:
A⁺A⁺B⁰B⁰C⁰C⁰D⁰D⁰ and A⁰A⁰B⁺B⁺C⁺C⁺D⁺D⁺ and the number of additive alleles on each genotype are two and six respectively.
The cross between both F1 traits will yield an heterozygous individual for the offspring. i.e A⁺A⁰B⁺B⁰C⁺C⁰D⁺D⁰ with only four additive allele