All categories

1 year ago

WILL GIVE BRAINLIEST THANK AND FIVE STAR!

Mathematics

2 answers:

Novay_Z [31]1 year ago

3 0

Answer:

y=−38x−14y is equal to negative 3 eighths x minus 1 fourth is the answer.

Naddik [55]1 year ago

3 0

Y= -38x-14y is equal to negative 3 eighths x minus 1 fourth

You might be interested in

Arithmetic sequence

HACTEHA [7]

Answer:18

Step-by-step explanation:

Note: Mathematicians start counting at 1, so by convention, n=1 is the first term. So we must define what the first term is. Then we have to figure out and include the common difference.

Taking a look at the examples again,

Sequence: 1, 2, 3, 4, … | Formula: a(n) = n + 1 | Recursive formula: a(n) = a(n-1) + 1, a(1) = 1

Sequence: 3, 8, 13, 18, … |Formula: b(n) = 5n - 2 | Recursive formula: b(n) = b(n-1) + 5, b(1) = 3

8 0

2 years ago

You just obtained a credit card. You immediately purchase a stereo system for $200. your credit limit is $1000. Let's assume tha

deff fn [24]

Answer:

i think the answer is:

B. 0.0142

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Complex numbers [ = square root symbol -[-64 How would I find this?

cestrela7 [59]

$-\sqrt{-64}=-\sqrt{8^2\cdot (-1)}-8\sqrt{-1}=-8i$

8 0

2 years ago

Find a homogeneous linear differential equation with constant coefficients whose general solution is given by

frez [133]

Answer:

$y" + 2y' + 2y = 0$

Step-by-step explanation:

Given

$y=c_1e^{-x}cosx+c_2e^{-x}sinx$

Required

Determine a homogeneous linear differential equation

Rewrite the expression as:

$y=c_1e^{\alpha x}cos(\beta x)+c_2e^{\alpha x}sin(\beta x)$

Where

$\alpha = -1$ and $\beta = 1$

For a homogeneous linear differential equation, the repeated value m is given as:

$m = \alpha \± \beta i$

Substitute values for $\alpha$ and $\beta$

$m = -1 \± 1*i$

$m = -1 \± i$

Add 1 to both sides

$m +1= 1 -1 \± i$

$m +1= \± i$

Square both sides

$(m +1)^2= (\± i)^2$

$m^2 + m + m + 1 = i^2$

$m^2 + 2m + 1 = i^2$

In complex numbers:

$i^2 = -1$

So, the expression becomes:

$m^2 + 2m + 1 = -1$

Add 1 to both sides

$m^2 + 2m + 1 +1= -1+1$

$m^2 + 2m + 2= 0$

This corresponds to the homogeneous linear differential equation

$y" + 2y' + 2y = 0$

6 0

2 years ago

PLZ HELP!!!!!!! Evaluate. 43−4÷2⋅5 20 40 54 150

vitfil [10]

Isnt it 33 ////??? thats what i got.

6 0

2 years ago

Read 2 more answers