Answer:
Refer below
Step-by-step explanation:
a) a and b are the lower and higher values of the interval for which uniform distribution is defined.
Here a= 6 and b =10
b) Mean of the uniform distribution= (a+b)/2 = (6+10)/2 =8
Or int x (1/4) dx = x^2/8 = 8
c) Variance of the uniform distribution = (b^2-a^2)/12 = (100-64)/12
= 36/12 =3
Std dev = sq rt of 3 = 1.732
d) To find total area
PDF of the distribution = 1/(b-a) = 1/4, 6<x<10
Area = \int 6 to 10 of 1/4 dx
= x/4
Subtitute limits
= (10-6)/4 =1
So total area = 1
d)P(X>7) = int 7 to 10 of 1/4 dx = 3/4
e) P(7<x<9) = Int 7 to 9 of 1/4 dx = 2/4 = 1/2
The answer to the question is 9
Answer: 192 in.2
Step-by-step explanation:
Answer:
Option B
Step-by-step explanation:
Surface area of a triangular prism = Area of the triangular sides + Area of the rectangular sides
Area of the triangular sides = 2(Area of the triangular base)
= ![2[\frac{1}{2}(\text{Base})(\text{Height})]](https://tex.z-dn.net/?f=2%5B%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BBase%7D%29%28%5Ctext%7BHeight%7D%29%5D)
= 10 × 12
= 120 ft²
Area of the rectangular sides = (Perimeter of the triangular side)(Height of the prism)
= (10 + 13 + 13)(15)
= 36 × 15
= 540 ft²
Surface area of the prism = 120 + 540
= 660 square feet
Option B will be the answer.