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2 years ago

5

Question Number 2!! Thank youu

1 answer:

rewona [7]2 years ago

3 0

Answer:

56°

Step-by-step explanation:

Since triangle ABD and triangle CBD are congruent (SAS), so you can divide m∠ABC by 2 to get the m∠ABD and m∠CBD, or 56°.

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Mark and ann together were allocated n boxes of cookies to sell for a club project. mark sold 10 boxes less than n and ann sold

Lady bird [3.3K]

<span>n = 11<span>.

Explanation:
Let m be the number of boxes Mark sells and a be the number of boxes Ann sells.

Since Mark sells 10 less than n, m = n-10. Since Ann sells 2 less than n, a = n-2.

Together, they sold n-10+n-2=2n-12 boxes.

We know that they sold less than n boxes, so our inequality would be
2n-12<n.

To solve this, subtract n from both sides:
2n-12-n<n-n; n-12<0.

Add 12 to both sides:
n-12+12<0+12; n<12.

This means there were less than 12 boxes. The next number down is 11; this woks because Mark sold 10 less than n; 11-10=1. Mark sold at least 1 box.

If n=10, however, 10-10=0; this doesn't work, because Mark did sell at least 1 box. </span></span>

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3 years ago

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Find all positive integer values of c that make x^2+6x+c factorable

densk [106]

It's factorable when c ∈ {5,8,9}

6 0

4 years ago

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that

Helga [31]

Answer:

$\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n$

Step-by-step explanation:

Rn(x) →0

f(x) = 10/x

a = -2

Taylor series for the function <em>f </em>at the number a is:

$f(x) = \sum^\infty_{n=0} \frac{f^{(n)}(a)}{n!} (x - a)^n$

$f(x) = f(a) + \frac{f'(a)}{1!}(x-a)+\frac{f"(a)}{2!} (x-a)^2 + ...$ ............ equation (1)

Now we will find the function <em>f </em> and all derivatives of the function <em>f</em> at a = -2

f(x) = 10/x f(-2) = 10/-2

f'(x) = -10/x² f'(-2) = -10/(-2)²

f"(x) = -10.2/x³ f"(-2) = -10.2/(-2)³

f"'(x) = -10.2.3/x⁴ f'"(-2) = -10.2.3/(-2)⁴

f""(x) = -10.2.3.4/x⁵ f""(-2) = -10.2.3.4/(-2)⁵

∴ The Taylor series for the function <em>f</em> at a = -4 means that we substitute the value of each function into equation (1)

So, we get $\sum^\infty_{n=0} - \frac{10(x+2)^n}{2^{n+1}}$ Or $\sum^\infty_{n=0} -5 (\frac{x+2}{2})^n$

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3 years ago

Indicate in standard form the equation of the line passing through the given points.

lorasvet [3.4K]

Answer:

y = 6

Step-by-step explanation:

Let the y-intercept form of the equation of the line is,

y = mx + b

Here, m = Slope of the line

b = y-intercept

Slope of the line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by,

m = $\frac{y_2-y_1}{x_2-x_1}$

Slope of the passing through (0, 6) and (5, 6) will be,

m = $\frac{6-6}{0-5}$

m = 0

Equation of the line with m = 0 will be,

y = 0 + b

y = b

Since, line passes through (0, 6),

By substituting the values in the equation,

b = 6

Therefore, standard equation of the line passing through (0, 6) and (5, 6) will be,

y = 6

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3 years ago

Which of the following statements are true about the graph? Check all that apply.

Alenkasestr [34]

Answer:

the graph has a minimum

Step-by-step explanation:

the minimum is -9

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2 years ago

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