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3 years ago

5.84 to the nearest cenft

Mathematics

1 answer:

serg [7]3 years ago

4 0

Answer:

$5.85

Step-by-step explanation:

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khan academy is giving me only this explanation but won't go into detail and I cannot understand it for the life of me. how do I

Setler [38]

Answer:

12 - 4i

Step-by-step explanation:

-2i ( 2+6i)

Distribute

-2i * 2 + -2i *6i

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We know that i^2 = -1 so replace it

-4i - 12(-1)

-4i + 12

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12 - 4i

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3 years ago

Some people want peace and quiet, i want world peace and quiet...

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Answer:

same here too much ppl dieing

Step-by-step explanation:

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3 years ago

Round the following numbers to the nearest 1000

Fed [463]

Answer:

A. 5000 B: 12000 C 57000

Step-by-step explanation:

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3 years ago

Read 2 more answers

At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

$P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%$

Hence, a) 4.6798, and b) 19.8%.

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4 years ago

Write the standard form of the line passing through the following points (-5,1) and (0,-5)

Ronch [10]

Answer:

-6/5

Step-by-step explanation:

-5-1 / 0-(-5)

3 0

3 years ago