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dlinn [17]
3 years ago
6

What is the ratio of y to x? Without extending the table, what would the value for y be when x = 54?

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
8 0
The y is going to be 165 if the x is 54 because you need to multiply by 3 each time.
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Please help. Sine and Cosine rules
kodGreya [7K]

Answer:

a=41.8 BC=2.8

Step-by-step explanation:

sin30/6=sinx/8

8*sin30=6sinx

4=6sinx

sin^-1(4/6)

angle a

cosine rule

bc^2=3^2 +5^2-2(3)(5)*cos30

BC^2=\sqrt8.019237886\\

BC=2.83

2.8

3 0
3 years ago
(-3,8) (2, - 11)
lesya692 [45]
Not sure what your asking here
4 0
3 years ago
Can it be concluded that if there is a 50% chance of contracting a communicable disease through contact with an infected person,
crimeas [40]

Answer:

No it cannot be concluded.

Step-by-step explanation:

The probability of getting the disease in the first attempt is 50%

The probability of getting the disease in the second attempt is 50%

Thus the probability of getting the disease in either of the turns is 50%+50%=100% (which may seem to be true)

BUT

The probability of not  getting the disease in the first attempt is 50%

The probability of not getting the disease in the second attempt is 50%

Thus the probability of not getting the disease in either of the turns is 50%+50%=100% (which is also true for this case)

Thus the probability of getting the disease in either of the 2 contacts is still 50%

4 0
3 years ago
Each of six jars contains the same number of candies. Alice moves half of the candies from the first jar to the second jar. Then
tino4ka555 [31]

Answer:

The number of candies in the sixth jar is 42.

Step-by-step explanation:

Assume that there are <em>x</em> number of candies in each of the six jars.

⇒ After Alice moves half of the candies from the first jar to the second jar, the number of candies in the second jar is:

\text{Number of candies in the 2nd jar}=x+\fracx}{2}=\frac{3}{2}x

⇒ After Boris moves half of the candies from the second jar to the third jar, the number of candies in the third jar is:

\text{Number of candies in the 3rd jar}=x+\frac{3x}{4}=\frac{7}{4}x

⇒ After Clara moves half of the candies from the third jar to the fourth jar, the number of candies in the fourth jar is:

\text{Number of candies in the 4th jar}=x+\frac{7x}{4}=\frac{15}{8}x

⇒ After Dara moves half of the candies from the fourth jar to the fifth jar, the number of candies in the fifth jar is:

\text{Number of candies in the 5th jar}=x+\frac{15x}{16}=\frac{31}{16}x

⇒ After Ed moves half of the candies from the fifth jar to the sixth jar, the number of candies in the sixth jar is:

\text{Number of candies in the 6th jar}=x+\frac{31x}{32}=\frac{63}{32}x

Now, it is provided that at the end, 30 candies are in the fourth jar.

Compute the value of <em>x</em> as follows:

\text{Number of candies in the 4th jar}=40\\\\\frac{15}{8}x=40\\\\x=\frac{40\times 8}{15}\\\\x=\frac{64}{3}

Compute the number of candies in the sixth jar as follows:

\text{Number of candies in the 6th jar}=\frac{63}{32}x\\

                                                    =\frac{63}{32}\times\frac{64}{3}\\\\=21\times2\\\\=42

Thus, the number of candies in the sixth jar is 42.

4 0
3 years ago
How can i find the volume of a rectangular prism
Lubov Fominskaja [6]

Answer:

Width x height x length

Step-by-step explanation:

You just multiply the width times the height times the length.

4 0
3 years ago
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