Question

Some information about a direct variation is given in the table below. If the equation

Answer 1

Answer:

Step-by-step explanation:

y = kx ;

k = $\frac{y}{x}$ ; x = $\frac{y}{k}$

~~~~~~~~~~~~~

k = $\frac{1}{2}$ ÷ 1 = $\frac{1}{2}$

$y_{1}$ = $\frac{1}{2}$ × ( - 8 ) = - 4

$y_{2}$ = $\frac{1}{2}$ × ( - 4 ) = - 2

$y_{3}$ = $\frac{1}{2}$ × 2 = 1

$x_{5}$ = $\frac{1}{3}$ ÷ $\frac{1}{2}$ = $\frac{2}{3}$

$x_{6}$ = - $\frac{1}{4}$ ÷ $\frac{1}{2}$ = - $\frac{1}{2}$

$x_{7}$ = 0

( x , y ) : ( - 8 , - 4 ), ( - 4 , - 2 ), ( 2 , 1 ), ( 1 , $\frac{1}{2}$ ), ( $\frac{2}{3}$ , $\frac{1}{3}$ ), ( - $\frac{1}{2}$ , - $\frac{1}{4}$ ), ( 0 , 0 )