Question

Find an equation for the perpendicular bisector of the line segment whose endpoints are (-4,-5)and (8,-9)

Answer 1

Answer:

y = 3x - 13

Step-by-step explanation:

slope of line segment is -1/3 so a segment perpendicular to this would need a slope of 3

the midpoint for the segment is (2, -7); midpoint formula is [($x_{1}$+$x_{2}$/2), ($y_{1}$+$y_{2}$/2)]

using slope of 3 and point (2, -7) we can plug into y = mx + b

-7 = 3(2) + b

-7 = 6 + b

b = -13