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Veseljchak [2.6K]
3 years ago
12

Help me please I appreciate it

Mathematics
1 answer:
KonstantinChe [14]3 years ago
5 0

Answer: (-2,-4)  

Step-by-step explanation:

To find the midpoint between two points we need to find the mean average between the x  and the y .

Since we know the midpoint  will have to represent the missing coordinates by the variables.

\frac{-6+x}{2} = -4     Solve for x to find the x coordinate by first multiplying both sides by -4.

-6 + x = -8        Add -6 to both sides

+6        +6  

x = -2  

The x coordinate of the B is -2  now  we need to find the y coordinate.

\frac{4+y}{2} = 0     Multiply both sides by 2

4 + y = 0     Subtract 4 from both sides

-4        -4

y = -4  

The y coordinate is -4  so the coordinates will be  (-2,-4)

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Find dy/dx for 4 - xy = y^3
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Answer:

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\frac{d(4-xy)}{dx}=\frac{d(y^3)}{dx}\\ \frac{d(4)}{dx}-\frac{d(xy)}{dx}=3y^{3-1}\frac{dy}{dx}\\ 0-(\frac{dx}{dx}y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(1y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -y-x\frac{dy}{dx}=3y^2\frac{dy}{dx}

Solving for dy/dx: Addind x dy/dx both sides of the equation:

-y-x\frac{dy}{dx}+x\frac{dy}{dx}=3y^2\frac{dy}{dx}+x\frac{dy}{dx} \\ -y=3y^2\frac{dy}{dx}+x\frac{dy}{dx}

Common factor dy/dx on the right side of the equation:

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Dividing both sides of the equation by 3y^2+x:

\frac{-y}{3y^2+x}=\frac{(3y^2+x)}{3y^2+x}\frac{dy}{dx}\\ -\frac{y}{3y^2+x}=\frac{dy}{dx}\\ \frac{dy}{dx}=-\frac{y}{3y^2+x}

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3 years ago
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After Applying Laws of Exponents we can write as (6yz)^{-4}

<h3>What is law of exponents ?</h3>

The exponent of a number indicates how many times a number has been multiplied by itself. For instance, 34 indicates that we have multiplied 3 four times. Its full form is 3 3 3 3. Exponent is another name for a number's power. A whole number, fraction, negative number, or decimal are all acceptable.

<h3>How are powers of powers multiplied?</h3>

Exponents with distinct bases and the same powers can be multiplied by multiplying the bases and writing the power outside of the brackets.

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