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katovenus [111]
2 years ago
5

Solve for q: s = 4p + 4q

Mathematics
1 answer:
MArishka [77]2 years ago
3 0

Answer:

Step-by-step explanation:

s = 4p + 4q

4p + 4q = s

Subtract 4p from both sides

4q = x - 4p

Divide both sides by 4

\dfrac{4q}{4}=\dfrac{s-4p}{4}\\\\\\q= \dfrac{s-4p}{4}

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you start out driving from your house to an old friends house in a different town, which is 280 miles away. after an hour and a
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You would take 280-105=175 miles away and take 105 and divide that by your time 1.5 too get 70 mph
5 0
3 years ago
Choose as many answers as apply.
Pie

Answer:

b,c,d

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The perimeter of a rectangular metal plate is 15 cm. Find the length of the rectangular plate (in decimals) whose width is 228 c
scoray [572]

The Solution.

Representing the problem in a diagram, we have

By formula,

P=2(L+W)

In this case,

P=15\operatorname{cm},L=?,W=\frac{22}{8}cm

Substituting these values in the formula above, we get

15=2(L+\frac{22}{8})

Clearing the bracket, we get

15=2L+(2\times\frac{22}{8})\begin{gathered} 15=2L+\frac{11}{2} \\  \\ 15=2L+5.5 \end{gathered}\begin{gathered} 15-5.5=2L \\ 9.5=2L \end{gathered}

Dividing both sides by 2, we get

L=\frac{9.5}{2}=4.75\approx4.8\operatorname{cm}

Therefore, the correct answer is option C.

6 0
1 year ago
Michael baked 60 oatmeal cookies and 45 chocolate chip cookies to package in plastic containers for her friends at school. She w
Scrat [10]

Answer:

3

Step-by-step explanation:

Michael must find the smallest number possible that can divide 60 and 45 then take the two quotients after dividing the 2 types of cookies by the smallest number possible.

2 is not possible as 45 is an odd number

3 can divide both 60 and 45

60/3 = 20 oatmeal cookies in each container.

45/3 = 15 chocolate chip cookies in each container.

7 0
3 years ago
A chemist whishes to prepare 100 liters of 45% purity of sulphuric acid .He has two kinds of acid solutions in stock ,one is 55%
tester [92]

Answer:

the chemist should use 60 liters of 55% solution and 40  litres of 30% solution in order to prepare 100 liters of 45% purity of sulphuric acid.

Step-by-step explanation:

From the given information,

Let x be the litres of 55% pure solution

Let y be the litres of 30% pure solution

Also;

Given that our total volume of solution is  100 litres

x+y =100  ---- (1)

The total solution of pure by related by the sum of the individual pure concentrations to make up the concentration of final solution.

(0.55)(x)+(0.30)(y) = 0.45(100) ---- (2)

From equation (1)

Let ; y = 100 - x

Replacing the value for y = 100 - x into equation (2)

(0.55)(x)+(0.30)(100-x) = 0.45(100)

0.55x + 30 - 0.30x = 45

0.55x - 0.30x = 45 - 30

0.25x = 15

x = 15/0.25

x = 60 liters of 55% solution

From ; y = 100 - x

y = 100 - 60

y = 40  litres of 30% solution.

Therefore, the chemist should use 60 liters of 55% solution and 40  litres of 30% solution in order to prepare 100 liters of 45% purity of sulphuric acid.

7 0
3 years ago
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